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just olya [345]
4 years ago
13

What is the fundamental relationship among speed (u), density (k), and flow (q)?

Physics
1 answer:
Semenov [28]4 years ago
3 0

The representation of the traffic flow is determined by three main characteristics of this: The flow, the density and the speed. The relationship between the three helps to improve the design of the roads as well as all kinds of facilities operations.

The mathematical relationship that groups them is given by the function:

q = k*\nu

Where,

\nu= Speed

k = Density

q = Flow

Through it it is possible to obtain properties of this by which,

  • When the density on the road is zero, the flow is also zero because there are no vehicles on the road
  • As the density increases, the flow increases
  • When the density reaches a maximum jam density, the flow must be zero because the vehicles will line up from end to end
  • The flow will also increase to a maximum value, increases in density beyond that point result in flow reductions.
  • Speed is the average speed of space.

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A diffraction grating, ruled with 300 lines per mm, is illuminated with a white light source at normal incidence.
Vera_Pavlovna [14]

the expression for diffraction grating allows to find the results for the questions for the angular separation are:

i) The third order is Δθ = 0.203 rad.

ii) The first order with water is Δθ = 0.046 rad.

The diffraction grating is a system formed by a large number of equally spaced lines whose diffraction is given by the expression.

          d sin θ = m λ

Where d is the distance between two lines, θ is the angle of diffraction, the order of diffraction and λ is the wavelength.

i) Let's start by looking for the separation between two lines

Let's use a rule of direct proportions. If there are 300 lines in 1 mm, what distance is there between two lines.

         d = 1 lines (1 mm / 300 lines) = 3,333 10⁻³ mm

         d = 3.333 10⁻⁶ m

Let's find the angle of diffraction for the third order (m = 3) for each wavelength.

λ₁ = 400 nm = 400 10⁻⁹ m

         sin θ₁ = \frac{m \ \lambda }{d}m λ/ d

         sin θ₁ = \frac{3 \ 400 \ 10^{-9} }{3.333 \ 10^{-6} }  

         θ₁ = sin⁻¹ 0.3600

         θ₁ = 0.368 rad

λ₂ = 600 nm = 600 10⁻⁹ m

         sin θ₂ = \frac{3 \ 600 \ 10^{-9} }{3.333 \ 10^{-6} }  

         θ₂ = sin⁻¹ 0.5401

         θ₂ = 0.571 rad

The angular separation is

         Δθ = θ₂ - θ₁

         Δθ = 0.571 - 0.368

         Δθ = 0.203 rad

ii) In this case, the separation between the network and the observation screen is filled with water.

When the rays leave the network they undergo a refraction process, for which they must comply with the relationship.

           n_i \ sin \theta_1 = n_r \ sin \theta_r

The incident side is in the air, therefore its refractive index is n_i = 1 and when it passes into the water with refractive index n_r = 1.33.

Let's start looking for the incident angles for the first order of diffraction.

      m = 1

λ₁ = 400 nm

         θ₁ = sin⁻¹  \frac{1 \ 400 \ 10^{-9}}{3.33 \ 10^{-6}}

         θ₁ = 0.120 rad

λ₂ = 600 nm

        θ₂ = sin⁻¹¹ \frac{1 \ 600 \ 10^{-9} }{3.33 \ 10^{-6}}

        θ₂ = 0.181 rad

we use the equation of refraction.

         \theta_r  = sin⁻¹ (\frac{n_i}{n_r} \ sin \ \theta_i )

λ₁ = 400 nm  

       θ₁ = sin¹ (\frac{1 sin 0.120}{1.33}

       θ₁ = 0.090 rad

λ₂ = 600 nm

        θ₂ =sin⁻¹  \frac{1 sin 0.181}{1.33}

        θ₂ = 0.1358 rad

The angular separation is

          Δθ = 0.1358 - 0.090

          Δθ = 0.046 rad.

In conclusion using the relation for the diffraction grating we can find the results for the questions about angular separation are:

       i) The third order is Δθ = 0.203 rad.

      ii) The first order with water is Δθ = 0.046 rad.

Learn more here: brainly.com/question/473160

6 0
3 years ago
Juan measured the temperature of salt water. He then added 273 to the measured value. Which conversion is Juan m
lara31 [8.8K]

Degree Celsius to Kelvin

<u>Explanation</u>:

  • Two units of measuring temperature are Degree Celsius and Kelvin.
  • A measured value in degree Celsius can be converted to Kelvin by adding 273 to it. Here, Juan is doing that conversion - degree Celsius to Kelvin.
  • °C + 273 = K
6 0
4 years ago
A 8.0-g bullet with an initial velocity of 115.0 m/s lodges in a block of wood and comes to rest at a
Gnesinka [82]
A. When your fire a bullet into the air, it typically takes between 20 and 90 second for it to come down,depending on the angle it was fired at,its muzzle velocity and caliber.
3 0
3 years ago
A lunar eclipse can only happen during a(1) new moon.(2) solstice.(3) first quarter moon.(4) full moon.(5) perihelion passage of
Ray Of Light [21]

Answer:

(4) full moon.

Explanation:

Lunar eclipse can only occur on a full moon night when the sun the earth and the moon are very much in a straight line.

During this period the the light of the sun that incidents on the moon is blocked by the earth and so we have the phases of the moon due to the relative motion of the three bodies which partially enables the light of the sun to reach the moon.

The moon appears orange-red during this time because the light that reaches the moon is after the refraction through the earth's atmosphere from which the other wavelengths have been absorbed by the earth's atmosphere.

Lunar eclipse can only occur at night and hence it can only be observed from about half of the earth.

7 0
3 years ago
If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Mrrafil [7]

Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

5 0
3 years ago
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