Answer:
The molarity of the NaOH solution is 0.076 M
Explanation:
Step 1: Data given
Mass of oxalic acid = 192 mg = 0.192 grams
volume = 250 mL = 0.250 L
Molar mass oxalic acid = 90.03 g/mol
Step 2: The balanced equation
H2C2O4 + 2NaOH → Na2C2O4 + H2O
Step 3: Calculate moles of oxalic acid
Moles oxalic acid = 0.192 grams / 90.03 g/mol
Moles oxalic acid = 0.00213 moles
Step 4: Calculate molarity of oxalic acid
Molarity = Moles / volume
Molarity = 0.00213 moles / 0.250 L
Molarity = 0.00852 M
Step 5: Calculate Molarity of NaOH
2
Ca*Va = Cb*Vb
with Ca = Molarity of oxalic acid = 0.00852 M
with Va = volume of oxalic acid = 0.250 L
with Cb = Molarity of NaOH = TO BE DETERMINED
with Vb = volume of 0.0558 L
Cb = (2*0.00852 * 0.25) / 0.0558
Cb = 0.076 M
The molarity of the NaOH solution is 0.076 M
