The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm
The instantaneous velocity is how the position is changing with respect to time in a specific point in time, as opposed to the average value given by Delta(x)/Delta(t). It's given by taking a limit of Delta(x)/Delta(t) where t approaches 0, that is, by derivating x(t) in respect to t.
v(t) = x'(t) = (28 + 12.4t + 0.045t^3)' = 12.4 + 0.135t^2
But we want to find the velocity at t = 8s:
v(8) = 12.4 + 0.135*(8)^2 = 21.04m/s
Explanation:
density = mass/ volume
in the question the mass is given in grams so will convert it into kg,
10 g = 0.01 kg
density= 0.01/ 20 = 1 / 2000 = 0.005 kg/m^3
The hotter molecules become, the faster they move around. The colder they are, the more slow and lethargic they are
The radio waves travels between the two boxes and they were travelling through air,
- Box B captures, amplifies and demodulates radio waves.
- Box A modulates, amplifies and send out radio waves.
<h3>What are radio waves?</h3>
- Radio waves are the type of radiation from the electromagnetic spectrum.
- The radio waves can be used in communication technologies like computer, phones, radios , etc..
- Radio waves have lower frequencies but longer wavelength.
- These devices will get signal and then it transmit as mechanical waves through sound.
In that way, the radio waves from box A to B through air, the box A will gets the signal, and then modulates, amplifies and then it send out radio waves. Through the air, Box B will captures, amplifies and demodulates radio waves.
Learn more about radio waves,
brainly.com/question/13989450
#SPJ1
