Explanation:
what is the force
ican't under stand these question
The airtime is 9.8
the velocity is 0
Answer:
See below
Explanation:
Vertical position = 45 + 20 sin (30) t - 4.9 t^2
when it hits ground this = 0
0 = -4.9t^2 + 20 sin (30 ) t + 45
0 = -4.9t^2 + 10 t +45 = 0 solve for t =4.22 sec
max height is at t= - b/2a = 10/9.8 =1.02
use this value of 't' in the equation to calculate max height = 50.1 m
it has 4.22 - 1.02 to free fall = 3.2 seconds free fall
v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL
it will <u>also</u> still have horizontal velocity = 20 cos 30 = 17.32 m/s
total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s
Horizontal range = 20 cos 30 * t = 20 * cos 30 * 4.22 = 73.1 m
Answer:
c = 4
Explanation:
From work-energy theorem KE = workdone.
Given F = (cx - 3.00x²)i
W = ∫Fdx = ∫(cx - 3.00x²)dx = cx²/2 –3.00x³/3 + A
W = cx²/2 –x³ + A
Where A is a constant
At x = 0, KE = 20J
So W = 20J at x = 0
20 = c×0 - 0 +A
A = 20
So W = cx²/2 –x³ + 20
Also when x = 3.00m, W = KE = 11J
So
11 = c×3²/2 – 3³ + 20
11 = 4.5c – 7
4.5c = 11 + 7
4.5c = 18
c = 18/4.5 = 4
c = 4
