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<h3>
Answer:</h3>
126.14 g
<h3>
Explanation:</h3>
- Complete combustion of hydrocarbons yields water and carbon dioxide.
- Methane is a hydrocarbon in the homologous series known as alkanes.
- Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.
CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)
<u>We are given;</u>
We are required to determine the mass of H₂O produced
<h3>Step 1: Moles of H₂O produced</h3>
- From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.
Therefore, Moles of methane = Moles of H₂O × 2
Hence, Moles of H₂O = 7.0 moles
<h3>Step 2: Mass of H₂O produced </h3>
We know that; mass = Moles × Molar mass
Molar mass of water = 18.02 g/mol
Therefore;
Mass of water = 7.0 moles × 18.02 g/mol
= 126.14 g
Thus, the mass of water produced is 126.14 g
The product of this reaction is a halohydrin as shown here.
<h3>What are the products?</h3>
We have a reaction that first involves the formation an alkene as the bases are used on the first substrate. The alkene that is thus created is now able to react with the bromine in water.
The first step of the reaction is where the multiple bond is created and this multiple bond is what can now go on to participate in a chemical reaction in the next step of the process of reaction as shown in the image.
Bromine in water is also hat we call bromine water. This bromine water is able to add across a double bond and when that happen we will have a saturated compound. This could also be regarded as halohydrin reaction.
Recall that the first step of the reaction of the alkene with bromine is the formation of a dibromide via the brominium intermediate. This is now followed by reaction with water to form the halohydrin product.
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According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
<h3>What is IUPAC convention?</h3>
IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).
Types of IUPAC Nomenclature of a few important aliphatic compounds:
- Alkane
- Alkene
- Alkyne
Example :
Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆
Formation of alkyl group:
Methane (CH₄) Remove 1 hydrogen (H) convert to methyl (H₃-C-)
Example: Propyl (-CH₃ - CH₂ - CH₂ - )
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
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Answer:
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
Explanation:
Given
1) NO(g) + Cl2(g) → NOCl2(g)
2) NOCl2(g) + NO(g) → 2NOCl(g)
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
k1= [NOCl2]
k-1= [NO] [Cl2]
k2 = [NOCl2] [NO]
Equilibrium for the first equation (reaction 1)
K= k1/k-1 = [NOCl2]/[NO] [Cl2]
Therefore
[NOCl2] = k1/k-1 [NO] [Cl2]
Rate= k2× k1/k-1 [NO]^2 [Cl2]
Rate = Koverall [NO]^2 [Cl2]
Where Koverall= k1k2/k-1
