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sergejj [24]
3 years ago
8

A plastic lime juice container in the shape of a sphere has a diameter of 4 cm.

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0
Vsphere=(4/3)pir³

d/2=r
given
d=4
d/2=r=4/2=2

Vsphere=(4/3)pi2³
Vsphere=(4/3)pi8
Vsphere=32/3pi
using pi=3.14
Vsphere=33.493333333333 cm³
round
Vsphere=33 cm³
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I got about 15.8 bushels of apples
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(x^7/8) (x^1/4)<br> Simplify the expression using the properties of exponents
valkas [14]

Answer:

x^9/8

Step-by-step explanation:

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An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that \pi = 0.2

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}

0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}

\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}

(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}

n = 5615

A sample size of 5615 is needed.

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Now \pi = 0.12, n = 5615.

We have to find M.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 2.81\sqrt{\frac{0.12*0.88}{5615}}

M = 0.012

7 0
3 years ago
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