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Given:
One midsegment of an equilateral triangle.
To find:
The ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths.
Solution:
All sides of an equilateral triangle are same.
Let a be the each side of the equilateral triangle.
Length of the midsegment is equal to the half of the non included side or third side.
The sum of two side is
Now, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is
Therefore, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is 1:4.
Answer:
- Three beers.
Step-by-step explanation:
The first mathematician orders 1 beer, the second orders 1/2 a beer, the third orders 1/4 a beer, the fourth orders 1/8 a beer, the fifth orders 1/16 a beer. . .
- The Sequence is:
- On observation, the next term is derived through the division of the previous term by 2.
- 2 is the constant factor
- Therefore, the bartender says 'Fine, I’ll just pour you two beers.'
Therefore, if the first mathematician orders 6 beers, the second orders 2 beer, the third orders 2/3 a beer, and so on
- The sequence is
- On observation, the next term is derived through the division of the previous term by 3.
- 3 is the constant factor
- Therefore, the bartender should pour three beers.
Answer:
The coordinates of EF are E(5,-4) and F(1,-4).
The line segment EF is in QIV
Step-by-step explanation:
The line segment AB has vertices at: A(-4,5) and B(-4,1).
We apply the rule to reflect AB in the y-axis to obtain CD.
We apply the rule to rotate CD 90 degrees clockwise about the origin to obtain EF.
The coordinates of EF are E(5,-4) and F(1,-4).
See attachment
