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svp [43]
4 years ago
14

Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o

C is 9.19 × 1023 m-3. The density and atomic weight (at 296°C) for this metal are 8.85 g/cm3 and 51.40 g/mol, respectively.
Physics
1 answer:
Schach [20]4 years ago
6 0

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

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Bess [88]

Answer:

Explanation:

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An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.

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Hope this helps!

4 0
3 years ago
An lc circuit oscillates at a frequency of 2000 Hz. What will the frequency be if the inductance is quadrupled?
Irina-Kira [14]
<h2>Answer:</h2>

An LC circuits if formed by an inductor and a capacitor. The charge on the capacitor and the current through the inductor both vary sinusoidally with time. Also, energy is transferred between magnetic energy in the inductor and electrical energy in the  capacitor. But <em>what happens with the frequency if the inductance is quadrupled? </em>that is, if initially the inductance is L and the frecuency f=2000Hz if now L_{New}=4L What will the frequency be? Well, we know that the frequency, inductance and capacitance are related as:

f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}}

and this equals 2000Hz. If now L is quadrupled:

f_{1}=\frac{1}{2\pi}\sqrt{\frac{1}{4LC}}=\frac{1}{2\pi}\sqrt{\frac{1}{4}}\sqrt{\frac{1}{LC}} \\ \\ \therefore f_{1}=(\frac{1}{2})\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \\ \\ \\ Since \ f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \ then: \\ \\ f_{1}=\frac{1}{2}f \therefore f_{1}=\frac{2000}{2} \\ \\ \therefore \boxed{f_{1}=1000Hz}

<em>Finally, if L is quadrupled the frequency is half the original frequency and equals 1000Hz</em>

3 0
3 years ago
When a positively charged body touches a neutral body, the neutral body will
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Become more positive instead of negative
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3 years ago
Since the moon orbits the earth approximately every 27 days, there is a lunar eclipse approximately every 27 days.
Dahasolnce [82]

Answer:

No ! its False

Explanation:

We all know , we dont have lunar eclipse in every 27 days . They do not happen every month because the Earth's orbit around the sun is not in the same plane as the Moon's orbit around the Earth.

5 0
3 years ago
A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from
Pavlova-9 [17]

Answer:

A) is repelled by the sphere.

Explanation:

On rubbing the plastic rod with the wool cloth the rod gains some electrons from the surface of the wool and becomes electrostatically negative in charge.

When this rod is brought near to a neutral metallic sphere then the electrons of the sphere get repelled from the nearest portion of the metallic sphere as it a conductor and the electrons accumulate on the farthest opposite side of the rod.

But when the rod is brought into contact for some time then the from the portion of the rod which is in contact to the sphere loses the electrons from that region to the sphere since plastic is not an electrical conductor so not all the charges travel to the sphere.

Then when the rod is separated, the charges on the sphere spread uniformly and the similar charged rod faces repulsion.

4 0
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