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NeTakaya
3 years ago
15

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 47.0 nC placed between q1

and q2 at x3 = -1.075 m ? Your answer may be positive or negative, depending on the direction of the force.

Physics
1 answer:
lesya [120]3 years ago
4 0

Answer:

Incomplete question, check attachment for completed question

Explanation:

The force of attraction between two forces are given as

F=kQq/r²

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In the formula vy=a t what is the value of a for an object in projectile motion
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I THINK that formula gives the vertical speed of a projectile at the time
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(I can't really be sure of anything, because whenever you show a formula
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If I'm on the right track, then the 'a' is the acceleration of gravity wherever
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8 0
3 years ago
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in
algol [13]

Answer: Magnitude of the force exerted on the egg by the ground is 9.2N

Explanation:

Given the following :

Mass of egg (m) = 150g = 0.15kg

Height(h) from which egg is dropped = 3m

velocity of egg before hitting the ground (u) = 4.4m/s

Final velocity of egg (V) = 0

Time taken (t) = 0.072s

Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:

Momentum = mass × velocity

From Newton's second law:

Force = mass × change in Velocity with time ;

That is

F = m * ΔV / t

Inputting our values

F = 0.15 * (4.4 - 0) / 0.072

F = 0.15 × (4.4 / 0.072)

F = 0.15 × 61.11

F = 9.16N

F = 9.2N

8 0
3 years ago
When placed in direct sunlight, which an object will absorb the most visible light energy
Vikentia [17]
I would guess anything that is black? black absorbs there most light energy. that's is why a black car in the sun will always be hotter inside than a white car.
3 0
3 years ago
When driving across Death Valley in the summertime, it is recommended that you release some air from your tires before making th
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Hot air rises ya fool ya fool
7 0
2 years ago
Read 2 more answers
An unknown substance has a mass of 0.125 kg and an initial temperature of 95.0°C. The substance is then dropped into a calorimet
mr Goodwill [35]

Answer:

c = 1163.34 J/kg.°C

Explanation:

Specific heat capacity:

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Use this equation:

mcΔT = ( mw c + mAl cAl )  ΔT'

Rearranging the equation to find the specific heat (c) you get this:

c = (( mw c + mAl cAl )  ΔT') / (mΔT)

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c = 1163.34 J/kg.°C

7 0
4 years ago
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