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IRISSAK [1]
3 years ago
15

Byun walked 15 blocks in 25 minutes. What was his average speed?

Physics
1 answer:
djverab [1.8K]3 years ago
8 0

Answer:

0.3m/s

Explanation:

speed=distance moved by the object/time taken

speed=15/25

speed=0.6

but we are asked to calculate average speed

so speed/2

average speed= 0.6/2

average speed=0.3m/s

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K20+H2O how many total oxygen atoms are there
kakasveta [241]
I think there would be 2 oxygen atoms,
If h2o is two hydrogen atoms and 1 oxygen atom then h2o has 2 potassium atoms and 1 oxygen atom, if you were to add them then together it would have 2 oxygen atoms, plz if I'm wrong correct me
8 0
3 years ago
What is the magnitude of the net torque on the pulley about the axle?
jeyben [28]

Answer: Torque= tangential force × radius of the pulley

Explanation:

Pulley is a simple machine which helps us to lift loads by applying the force in a convenient direction. It consists of a grooved wheel which is free to rotate about an axle passing through the center of the pulley.

For a pulley, the torque T= tangential force × radius of the pulley

Pulleys can be used in combination also to achieve a desired output.

6 0
3 years ago
If a high jumper needs to make his center of gravity rise 1.50 m, how fast must he be able to sprint? Assume all of his kinetic
sergiy2304 [10]

Answer:

v = 5.42 m/s

Explanation:

given,

height of the jumper = 1.5 m

velocity of sprinter = ?

kinetic energy can be transformed into potential energy

m g h = \dfrac{1}{2}mv^2

g h = \dfrac{1}{2}v^2

v =\sqrt{2gh}

v =\sqrt{2\times 9.8 \times 1.5}

v = 5.42 m/s

Speed of the sprinter is equal to v = 5.42 m/s

7 0
4 years ago
Alli was in the park playing on the equipment. she noticed that on the highest slide she slides down
LUCKY_DIMON [66]

Answer:

Is this answer complete????

3 0
3 years ago
Read 2 more answers
A bike with 15cm diameter wheels accelerates uniformly from rest to a speed of 7.1m/s over a distance of 35.4m. Determine the an
Finger [1]

Answer:

9.47 rad/s^2

Explanation:

Diameter = 15 cm, radius, r = diameter / 2 = 7.5 cm = 0.075 m, u = 0, v = 7.1 m/s,

s = 35.4 m

let a be the linear acceleration.

Use III equation of motion.

v^2 = u^2 + 2 a s

7.1 x 7.1 = 0 + 2 x a x 35.4

a = 0.71 m/s^2

Now the relation between linear acceleration and angular acceleration is

a = r x α

where,  α is angular acceleration

α = 0.71 / 0.075 = 9.47 rad/s^2

8 0
3 years ago
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