Answer:
The answer to your question is: letter A
Step-by-step explanation:
From the graph we get the points,
P (2,1)
Q (6,8)
Formula
d = √((x2-x1)² + (y2-y1)²)
d = √((6-2)² + (8-1)²)
d = √ (4² + 7²)
d = √ (16 + 49
d = √65 letter A
The answer is
The side length of the square Kevin cuts is slightly less than the length the instructor required
Answer:
A
B
-
4
x
+
9
B
C
=
5
x
+
2
=
A
=
9
x/
B
+
2/
B
−
9
C
A
C
−
56
=
A
=
9
x
/B
+
2/
B
−
9
C
x=A=9x/B+2x/B-9C
I hope this helps
Okay so first u just add the terms on each side
2t-18>-6-100t
2(t-9)>2(-3-50t)
t-9>-3-50t
51t>6
t>6/51
t>2/17
so just take a number line put an empty circle like this : O on 2/17 and draw a line showing it continues to the right infinitely. Sorry if my math is wrong lol i am functioning on one hour of sleep.
Answer:
Angle A must be acute.
Explanation:
Both angle A and C must be acute. The sum of the angles in a triangle is 180°.
An obtuse angle is more than 90°, so the sum of the remaining 2 angles has to be less than 90°.
Note that it is impossible to have:
<span>2 right angles in a triangle, because <span>90°+90°=180</span>° and the third angle still needs to be added.1 obtuse and 1 right angle in a triangle, their sum is more than 180°2 obtuse angles in a triangle, their sum is more than 180°</span>
It is possible to have an obtuse-angled isosceles triangle, but the vertex angle must be obtuse and the equal base angles will be acute.
