1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimaraw [331]
3 years ago
14

A disk shaped part is cast out of aluminum. Diameter of the disk = 650 mm and thickness = 16 mm. If the mold constant = 3.2 sec/

mm2 in Chvorinov's rule, how long will it take the casting to solidify
Engineering
1 answer:
Natasha_Volkova [10]3 years ago
3 0

Answer:

Time for solidification of the casting is 186 sec.

Explanation:

Chvorinov's rule is used to find the solidification time for any casting shape.

Step1

Given:

Diameter of the disk is 650 mm.

Thickness of the disk is 16 mm.

Chvorinov's rule constant is 3.2 sec/mm².

Step2

Calculation:

Total volume of the disk is calculated as follows:

V=\frac{\pi}{4}d^{2}t

V=\frac{\pi}{4}({650})^{2}\times({16})

V= 5309291.585 mm³.

Step3

Total surface area of the disk is calculated as follows:

A=\pi dt+2\times (\frac{\pi }{4}d^{2})

A=\pi \times 650\times 16+2\times (\frac{\pi }{4}\times 650^{2})

A= 696334.0117 mm².

Step4

Chvorinov's rule for time calculation is expressed as follows:

t=K(\frac{V}{A})^{2}

t=K(\frac{5309291.585}{696334.0117})^{2}

t=3.2(\frac{5309291.585}{696334.0117})^{2}

t=186 sec.

Thus, the time for solidification of the casting is 186 sec.

You might be interested in
In the circuit given below, R1 = 17 kΩ, R2 = 74 kΩ, and R3 = 5 MΩ. Calculate the gain 1formula58.mml when the switch is in posit
Elenna [48]

Answer:a

a) Vo/Vi = - 3.4

b) Vo/Vi = - 14.8

c) Vo/Vi = - 1000

Explanation:

a)

R1 = 17kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0

sin we know Va≈Vb=0

so

-Vi/5kΩ + -Vo/17kΩ = 0

Vo/Vi = - 17k/5k

Vo/Vi = -3.4

║Vo/Vi ║ = 3.4    ( negative sign phase inversion)

b)

R2 = 74kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

so

(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0

-Vi/5kΩ + -Vo/74kΩ = 0

Vo/Vi = - 74kΩ/5kΩ

Vo/Vi = - 14.8

║Vo/Vi ║ = 14.8  ( negative sign phase inversion)

c)

Also for ideal op-amp

Va≈Vb=0 so Va=0

Now for position 3 we apply nodal analysis we got at position 1

(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0           ( 5MΩ = 5000kΩ )

so

-Vi/5kΩ + -Vo/5000kΩ = 0

Vo/Vi = - 5000kΩ/5kΩ

Vo/Vi = - 1000

║Vo/Vi ║ = 1000  ( negative sign phase inversion)

3 0
3 years ago
An FPC 4 m2 in area is tested during the night to measure the overall heat loss coefficient. Water at 60 C circulates through th
sp2606 [1]

Answer:

<em> - 14.943 W/m^2K  ( negative sign indicates cooling ) </em>

Explanation:

Given data:

Area of FPC = 4 m^2

temp of water = 60°C

flow rate = 0.06 l/s

ambient temperature = 8°C

exit temperature = 49°C

<u>Calculate the overall heat loss coefficient </u>

Note : heat lost by water = heat loss through convection

m*Cp*dT  = h*A * ( T - To )

∴ dT / T - To = h*A / m*Cp  ( integrate the relation )

In ( \frac{49-8}{60-8} ) =  h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )

In ( 41 / 52 ) = 0.0159*h

hence h = - 0.2376 / 0.0159

              = - 14.943  W/m^2K  ( heat loss coefficient )

7 0
2 years ago
Fuel filters are being replaced on a HPCR diesel
saw5 [17]

Answer:) The correct answer is B. at the end of the fuel rail.

2) The one who is correct is the Technician A.

Explanation:

7 0
3 years ago
A medium-sized jet has a 3.8-mm-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to th
SCORPION-xisa [38]

Answer:

F_{thrust} ≅ 111 KN

Explanation:

Given that;

A medium-sized jet has a 3.8-mm-diameter i.e diameter (d) = 3.8

mass = 85,000 kg

drag co-efficient (C) = 0.37

(velocity (v)= 230 m/s

density (ρ) = 1.0 kg/m³

To calculate the thrust; we need to determine the relation of the drag force; which is given as:

F_{drag} = \frac{1}{2} × CρAv²

where;

ρ = density of air wind.

C = drag co-efficient

A = Area of the jet

v = velocity of the jet

From the question, we can deduce that the jet is in motion with a constant speed; as such: the net force acting on the jet in the air = 0

SO, F_{drag}-F_{thrust} = 0

We can as well say:

F_{drag}= F_{thrust}

We can now replace F_{thrust} with F_{drag} in the above equation.

Therefore, F_{thrust} = \frac{1}{2} × CρAv²

The A which stands as the area of the jet is given by the formula:

A=\frac{\pi d^2}{4}

We can now have a new equation after substituting our A into the previous equation as:

F_{thrust} = \frac{1}{2} × Cρ (\frac{\pi d^2}{4})v^2

Substituting our data from above; we have:

F_{thrust} = \frac{1}{2} × (0.37)(1.0kg/m^3)(\frac{\pi(3.8m)^2 }{4})(230m/s)^2

F_{thrust} = \frac{1}{8}   (0.37)(1.0kg/m^3)({\pi(3.8m)^2 })(230m/s)^2

F_{thrust} = 110,990N

F_{thrust}  in N (newton) to KN (kilo-newton) will be:

F_{thrust} = (110,990N)*\frac{1KN}{1,000N}

F_{thrust} = 110.990 KN

F_{thrust} ≅ 111 KN

In conclusion, the jet engine needed to provide 111 KN thrust in order to cruise at 230 m/s at an altitude where the air density is 1.0 kg/m³.

5 0
3 years ago
An amplifier which needs a high input resistance and a high output resistance is : Select one: a. A voltage amplifier b. None of
True [87]

Answer:

None of these

Explanation:

There are different types of amplifiers, and each has different characteristics.

  • Voltage amplifier needs high input and low output  resistance.
  • Current amplifier needs Low Input and High Output  resistance.
  • Trans-conductance amplifier Low Input and High Output resistance.
  • Trans-Resistance amplifier requires High Input and Low output  resistance.

Therefore, the correct answer is "None of these "

3 0
3 years ago
Other questions:
  • Find the difference between the first and third angle projection type.
    11·1 answer
  • The snowmobile has a weight of 250 lb, centered at G1, while the rider has a weight of 150 lb, centered at G2. Ifh=3ft, determin
    11·1 answer
  • How far do you jog each morning? You prefer to jog in different locations each day and do not have a pedometer to measure your d
    14·1 answer
  • 10. When an adhesion bond is made by melting a filler metal and allowing it to spread into the pores of the
    7·1 answer
  • A ball thrown vertically upward from the top of a building of 60ft with an initial velocity of vA=35 ft/s. Determine (a) how hig
    8·1 answer
  • List three reasons for surfacing metals.
    8·2 answers
  • Architects design roads.<br><br> A. True<br> B. False
    9·2 answers
  • How do you solve this. I dont know how so I need steps if you dont mind
    13·1 answer
  • Resistance depends on which three properties of a wire?
    15·1 answer
  • Can someone tell me what car, year, and model this is please
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!