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kondaur [170]
3 years ago
14

Employees cannot be held legally responsible for an environmental violation.

Engineering
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

It does not take into consideration what the responsible party knew about the law or regulation they violated. Environmental criminal liability is triggered through some level of intent.

You might be interested in
Disc brake rotors that are too thin cannot handle as much heat and will experience ___________.
konstantin123 [22]

Answer:

brake fade

Explanation:

Among the most frequent problems in the brake disc is their overheating. When there is overheating, the temperature of the disc rises to critical values, thus the brake pad starts to slide with respect to the disc, and the efficiency of the brake system decreases to a minimum.

Overheating of the brake disc is detected when inspecting the parts. Steel is the most common base material in the creation of brake discs. When heated, the material becomes its color. A disc of steel at critical temperature, turns bright orange and later on cooling becomes purple.

If a color change is seen on the brake discs when inspecting, a service station must be contacted without delay for an in-depth examination. After detecting the problem, the brake discs and pads will be changed in a mandatory way.

6 0
3 years ago
: The interior wall of a furnace is maintained at a temperature of 900 0C. The wall is 60 cm thick, 1 m wide, 1.5 m broad of mat
Snowcat [4.5K]

Answer:

<em>Heat is lost at the rate of 750 J/s or W</em>

<em>The thermal resistance is 1 K/W</em>

Explanation:

interior temperature T_{2} = 900 °C

wall thickness t = 60 cm = 0.6 m

width = 1 m

breadth = 1.5 m

thermal conductivity k = 0.4 W/m-K

outside temperature T_{1} = 150 °C

heat through the wall = ?

The area of the wall A = w x b = 1 x 1.5 = 1.5 m^2

Temperature difference dt = T_{2} - T_{1} = 900 - 150 = 750 °C

note that dt is also equal to 750 K since to convert from °C to K we'll have to add 273 to both temperature, which will still cancel out when we subtract the two temperatures.

To get the heat that escapes through the wall, we use the equation

Q = Ak\frac{dt}{t}

substituting values, we have

Q = 1.5 x 0.4 x \frac{750}{0.6} = <em>750 J/s or W</em>

Thermal resistance R_{t} = \frac{dt}{Q}

R_{t} = 750/750 =<em> 1 K/W</em>

7 0
3 years ago
Select the correct answer.
Ulleksa [173]
The answer is A. Immediately inform her colleague
4 0
3 years ago
Some of our modern kitchen cookware is made of ceramic materials. (a) List at least three important characteristics required of
Alisiya [41]

Answer:

A)

It should be Non- toxic

It should possess high Thermal conductivity

It should have the Required Thermal diffusivity

B)

  • stoneware : This material has good thermal diffusivity and it  is quite affordable and it is used in making pizza stones
  • porcelain: mostly used for mugs and it is non-toxic
  • Pyrex : posses good thermal conductivity used in oven

C)   All the materials are suitable because they serve different purposes when making modern kitchen cookware

Explanation:

A) characteristics required of a ceramic material to be used as a kitchen cookware

  • It should be Non- toxic
  • It should possess high Thermal conductivity
  • It should have the Required Thermal diffusivity

B) comparison of three ceramic materials as to their relative properties

  • stoneware : This material has good thermal diffusivity and it  is quite affordable and it is used in making pizza stones
  • porcelain: mostly used for mugs and it is non-toxic
  • Pyrex : posses good thermal conductivity used in ovens

C) material most suitable for the cookware.

 All the materials are suitable because they serve different purposes when making modern kitchen cookware

8 0
2 years ago
A standard penetration test has been conducted on a coarse sand at a depth of 16 ft below the ground surface. The blow counts ob
scoray [572]

Solution :

Given :

The number of blows is given as :

0 - 6 inch = 4 blows

6 - 12 inch = 6 blows

12 - 18 inch = 6 blows

The vertical effective stress $=1500 \ lb/ft^2$

                                              $= 71.82 \ kN/m^2$

                                             $ \sim 72 \ kN/m^2 $

Now,

$N_1=N_0 \left(\frac{350}{\bar{\sigma}+70} \right)$

$N_1 = $ corrected N - value of overburden

$\bar{\sigma}=$ effective stress at level of test

0 - 6 inch, $N_1=4 \left(\frac{350}{72+70} \right)$

                      = 9.86

6 - 12 inch, $N_1=6 \left(\frac{350}{72+70} \right) $

                        = 14.8

12 - 18 inch, $N_1=6 \left(\frac{350}{72+70} \right) $

                         = 14.8

$N_{avg}=\frac{9.86+14.8+14.8}{3}$

       = 13.14

       = 13

8 0
2 years ago
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