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3 years ago

Hi I'm trying to build a desk that moves up and down electrically but i need help

Engineering

1 answer:

gladu [14]3 years ago

6 0

There are tons of standing desks that you can buy that already do that. Might be where you want to look.

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Question #4

mihalych1998 [28]

Answer:

C. they need on the job experience I think

7 0

3 years ago

How do I put a picture on here for my graph equation??

Pavel [41]

Answer:

Take a screenshot of it and when you go to question you will see a paperclip looking thing

Explanation:

8 0

4 years ago

Read 2 more answers

Two point charges of values +2.0 and +5.5 μC, respectively, are separated by 0.50 m. What is the potential energy of this 2-char

IgorC [24]

Answer:

U=0.198J

Explanation:

The potential energy associated with two point charges is given as

U=(Kq1q2)/r

Where k=8.99*10⁹N.m²/C²

r=0.5m,

q₁=2μc,

q₂=5.5μc

If we substitute values into the equation we arrive at

U=(8.99*10⁹N.m²/C²* 2*10⁻⁶*5.5*10⁻⁶)/0.5

U=197.78*10⁻³

U=0.198J

From the calculation above, we can conclude that the potential energy between the two system of charges is 0.198J

8 0

4 years ago

Read 2 more answers

The barrel of a bicycle tire pump becomes quite warm during use. Explain the mechanisms responsible for the temperature increase

Alexeev081 [22]

Answer:

The air heats up when being compressed and transefers heat to the barrel.

Explanation:

When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.

In an adiabatic transformation:

$P^{1-k} * T^k = constant$

For air k = 1.4

$P0^{-0.4} * T0^{1.4} = P1^{-0.4} * T1^{1.4}$

$T1^{1.4} = \frac{P1^{0.4} * T0^{1.4}}{P0^{0.4}}$

$T1^{1.4} = \frac{P1}{P0}^{0.4} * T0^{1.4}$

$T1 = T0 * \frac{P1}{P0}^{0.4/1.4}$

$T1 = T0 * \frac{P1}{P0}^{0.28}$

SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.

After it was compressed the hot air will exchange heat with the barrel heating it up.

5 0

3 years ago

Water is to be boiled at sea level in a 30-cm-diameter stainless steel pan placed on top of a 3-kW electric burner. If 60 percen

hichkok12 [17]

Answer:

mevaporation=˙Qhfg=1. 8 kJ /s2269. 6 kJ /kg=0 . 793×10−3kg/ s=2. 855 kg /h

Explanation:

The properties of water at 1 atm and thus at the saturation temperature of 100C are hfg =2256.4 kJ/kg (Table A-4). The net rate of heat transfer to the water is ˙Q=0 . 60×3 kW=1 . 8 kWNoting that it takes 2256.4 kJ of energy to vaporize 1 kg of saturated liquid water, therate of evaporation of water is determined to be mevaporation=˙Qhfg=1. 8 kJ /s2269. 6 kJ /kg=0 . 793×10−3kg/ s=2. 855 kg /h

3 0

3 years ago