Answer:
The number of bright-dark fringe is 42
Solution:
As per the question:
Wavelength of light, 
Length of the glass cell, x = 3.73 cm = 0.0373 m
Refractive index, 
Now,
To calculate the bright-dark fringe shifts, we use the formula given below:

Now, substituting the appropriate values in the above formula:

≈ 42
An ideal voltage source provides no energy when it is loaded by an open circuit (i.e. an infinite impedance), but approaches infinite energy and current when the load resistance approaches zero (a short circuit). ... An ideal current source has an infinite output impedance in parallel with the source.
Answer:
Sensor/transducer: bimetallic thermometer
Output: displacement of thermometer tip
Control Tstages: mercury contact switch (open:furnace off; closed:furnace on
Explanation:
for a standard room thermostat
: This is the device that sets/determines the temperature of an enclosure.
Sensor/transducer: bimetallic thermometer: Bimetalic thermometer are used for measuring the temperature of the ambient air
. bimetallic thermometer actually contains two metals. they undergo linear expansivity as the temperature of the room changes.in other words, they experience contraction and expansion with increase or decrease in temperature.The sensor is basically coupled with a transducer which turns the measured variable(Temperature) into something else, such as a movement on a dial or an electrical signal
Output: displacement of thermometer tip
Controller: mercury contact switch (open:furnace off; closed:furnace on)
once the contact switch is open the furnace can go off. when the contact switch is closed, the furnace will come up.
R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
Read more about resistance here:
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Answer: (a) 36.18mm
(b) 23.52
Explanation: see attachment