Consider a section of muscle tissue of a cylindrical shape with a radius of 1.5 cm. During highly rigorous exercise, metabolic p
rocesses generate 15 kW/m3 of bulk tissue. The outer surface of the tissue is maintained at 37oC. The thermal conductivity of the muscle tissue is k =0.419 W/m*KDevelop a mathematical model to predict the steady-state temperature distribution, T(r), in the tissue along the radial position r. What is the temperature of the tissue at a distance of 0.75 cm from the surface?
1 answer:
Complete Question
The complete question is shown on the first uploaded image
Answer:
a)The mathematical model to predict the steady temperature distribution is
=
b)The mathematical model to predict the maximum temperature inside the muscle tissue is
=
c) The heat flux leaving the muscle is
= 1.06 W
d) The new maximum temperature within the muscle is
= 38.59°C
Explanation:
The explanation is shown on the second, third , fourth and fifth image
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The equations are based on the following assumptions
1) The bar is straight and of uniform section
2) The material of the bar is has uniform properties.
3) The only loading is the applied torque which is applied normal to the axis of the bar.
4) The bar is stressed within its elastic limit.
Nomenclature
T = torque (Nm)
l = length of bar (m)
J = Polar moment of inertia.(Circular Sections) ( m^4)
J' = Polar moment of inertia.(Non circluar sections) ( m^4 )
K = Factor replacing J for non-circular sections.( m^4)
r = radial distance of point from center of section (m)
ro = radius of section OD (m)
τ = shear stress (N/m^2)
G Modulus of rigidity (N/m^2)
θ = angle of twist (radians)
1) The bar is straight and of uniform section
2) The material of the bar is has uniform properties.
3) The only loading is the applied torque which is applied normal to the axis of the bar.
4) The bar is stressed within its elastic limit.
Nomenclature
T = torque (Nm)
l = length of bar (m)
J = Polar moment of inertia.(Circular Sections) ( m^4)
J' = Polar moment of inertia.(Non circluar sections) ( m^4 )
K = Factor replacing J for non-circular sections.( m^4)
r = radial distance of point from center of section (m)
ro = radius of section OD (m)
τ = shear stress (N/m^2)
G Modulus of rigidity (N/m^2)
θ = angle of twist (radians)