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3 years ago

8. What is the difference between mechanical waves and electromagnetic waves?

1 answer:

4 0

A electromagnetic waves are produced by the vibration of the charged particles in a mechanical wave is a wave that is not capable of transmitting its energy through a vacuum mechanical waves for cure a medium in order to transport their energy from one location to another is sound wave is an example of a mechanical wave

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1. Identify the significance of the following terms to the subject of the Civil War.

DanielleElmas [232]

What following terms I don’t see any please make your question clear

4 0

4 years ago

At each corner of a square of side there are point charges of magnitude Q, 2Q, 3Q, and 4Q

Bad White [126]

Answer:

$\displaystyle |F_t|=10.9\ \frac{KQ^2}{l^2}$

$\displaystyle \theta =68^o$

Explanation:

Electrostatic Force

It's the force that appears between two electrical charges q1 q2 when they are placed at a certain distance d. The force can be computed by using the Coulomb's law:

$\displaystyle F=\frac{KQ_1Q_2}{d^2}$

We have an arrangement of 4 charges as shown in the image below. We need to calculate the total force exerted on the charge 2Q by the other 3 charges. The free body diagram is also shown in the second image provided. The total force on 2Q is the vectorial sum of F1, F2, and F3. All the forces are repulsive, since all the charges have the same sign. Let's compute each force as follows:

$\displaystyle |F_1|=\frac{KQ(2Q)}{l^2}=\frac{2KQ^2}{l^2}$

$\displaystyle |F_2|=\frac{K(2Q)(4Q)}{l^2}=\frac{8KQ^2}{l^2}$

The distance between 3Q and 2Q is the diagonal of the rectagle of length l:

$\displaystyle |d_3|=\sqrt{l^2+l^2}=\sqrt{2}\ l$

The force F3 is

$\displaystyle |F_3|=\frac{K(3Q)(2Q)}{(\sqrt{2l)}^2}=\frac{3KQ^2}{l^2}$

Each force must be expressed as vectors. F1 is pointed to the right direction, thus its vertical components is zero

$\displaystyle \vec{F_1}=\left \langle |F_1|,0 \right \rangle=\left \langle \frac{2KQ^2}{l^2},0 \right \rangle$

F2 is pointed upwards and its horizontal component is zero

$\displaystyle \vec{F_2}=\left \langle 0,\frac{8KQ^2}{l^2} \right \rangle$

F3 has two components because it forms an angle of 45° respect to the horizontal, thus

$\displaystyle \vec{F_3}=\left \langle \frac{3KQ^2}{l^2}\ cos45^o,\frac{3KQ2}{l^2} sin45^o\right \rangle$

$\displaystyle \vec{F_3}=\left \langle \frac{3\sqrt{2}KQ^2}{2l^2},\frac{3\sqrt{2}KQ^2}{2l^2}\right \rangle$

Now we compute the total force

$\displaystyle \vec{F_t}=\vec{F_1}+\vec{F_2}+\vec{F_3}$

$\displaystyle \vec{F_t}=\left \langle \frac{2KQ^2}{l^2},0 \right \rangle +\left \langle 0,\frac{8KQ^2}{l^2} \right \rangle + \left \langle \frac{3\sqrt{2}KQ^2}{2l^2},\frac{3\sqrt{2}KQ^2}{2l^2}\right \rangle$

$\displaystyle \vec{F_t}=\left \langle \left(2+\frac{3\sqrt{2}}{2}\right)\frac{KQ^2}{l^2},\left(8+\frac{3\sqrt{2}}{2}\right) \frac{KQ^2}{l^2}\right \rangle$

$\displaystyle F_t=\left \langle 4.121,10.121 \right \rangle \frac{KQ^2}{l^2}$

Now we compute the magnitude

$\boxed{\displaystyle |F_t|=10.9\ \frac{KQ^2}{l^2}}$

The direction of the total force is given by

$\displaystyle tan\theta =\frac{10.121}{4.121}=2.4558$

$\boxed{\displaystyle \theta =68^o}$

6 0

3 years ago

What two processes practiced by scientists increase the likelihood of a successful outcome in science?

Amanda [17]

Answer:

ULTIMATE CORRECT ANSWER

collaboration and communication

Explanation:

5 0

3 years ago

To see her full heiht, a child that is 1 meter tall needs a mirror that is at least A) 033 m tall. 6) 050 m tall C) 075 m tall.

svlad2 [7]

Answer:

0.50 m tall

Explanation:

To see the full height of the child the height of the mirror should be half of the height of the child

As it id given that the height of the child is 1 meter so the height of the mirror is $=\frac{height\ of\ child}{2}=\frac{1}{2}=0.5m$

As it is a rule that to see the full any object the height of the mirror should be half of the height of the object

7 0

3 years ago

Why can the internal resistance of the DMM can be determined without taking into account the 100 Ω resistor? Could this be done

tester [92]

Answer:

Explanation:

For resistances in parallel we know that the overall resistance will be smaller in the value than any individual resistance. so, in this case we are concerned about $\frac{1}{R}$ = $\frac{1}{Rs}$ ⁺ $\frac{1}{Rp}$

where Rs is the series resistor and Rp is the parallel resistor.

so, R = 0.9M, roughly.

So, as the infernal resistance is very high as compared to the resistance conntected in parallel that is 100 Ω is not be used.

5 0

3 years ago