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choli [55]
3 years ago
8

plzzz PLZZZ PLZZZ HELP WILL GIVE BRAINLIST What is one thing you have learned about the platform of one of the Third Parties? Be

specific to which party.
Physics
2 answers:
ICE Princess25 [194]3 years ago
6 0

Answer:

Third parties may also help voter turnout by bringing more people to the polls. Third party candidates at the top of the ticket can help to draw attention to other party candidates down the ballot, helping them to win local or state office.

dexar [7]3 years ago
5 0

Answer:

IM answering so you can give the other guy brain cuz he smart.

Explanation:

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The body contains many small currents caused by the motion of ions in the organs and cells. Measurements of the magnetic field a
RoseWind [281]

Answer:

270 μA

Explanation:

Use the magnetic field due to long, straight wire and solve for current I.

B= \frac{\mu_0I}{2\pi r}

I= \frac{2\pi r B}{\mu_0}

plug in the values

I= \frac{2\pi(5.40\times10^{-2})\times10\times10^{-6}\times10^{-4}}{4\pi\times10^{-7}}

= 2.7×10^{-4)×10^6

=270 μA

The current that flows in the  heart is 270 μA

8 0
3 years ago
initially, a bowl holds 15 m^3 of water. an object is dropped into the bowl and the new volume of the water is 25 m^3. what is t
marusya05 [52]

Explanation:

The new volume of water = 25 ml

The old volume of water = 15 ml

The difference = 25 - 15 but what are the units?

Since the question asks for force, the units must start out as 10 mL

In water 1 mL has a mass of 1 gram, so the answer is 10 grams.

Grams are units of mass, not weight. You should convert this into newtons.

10 grams = 1/1000 = 0.01 kg

1 kg has a weight of 9.81 Newtons

0.01 kg has a weight 0.081 Newtons

If you have never seen a Newton before, then the answer is 10 grams

3 0
3 years ago
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
KatRina [158]

Answer:

E = kQs/r.r

Explanation:

Where E is the magnitude of electric field...

k is called Columb's Constant. It has a value of 8.99 x 109 N m2/C2.

Qs is the magnitude of the source charge...

and r is the magnitude of distance between source and target...

(When electron comes to rest Δt the magnitude of Electric field E become zero momentarily but later achieves the maximum value...)

5 0
3 years ago
A cart moving at 10 m/s is brought to a stop by the force plotted in the force-time graph shown here. Find the impulse and the a
Elena L [17]

Answer:

Impulse = 88 kg m/s

Mass = 8.8 kg

Explanation:

<u>We are given a graph of Force vs. Time. Looking at the graph we can see that the Force acts approximately between the time interval from 1sec to 4sec. </u>

Newton's Second Law relates an object's acceleration as a function of both the object's mass and the applied net force on the object. It is expressed as:

F=ma      Eqn. (1)

where

F : is the Net Force in Newtons ( N )

m : is the mass ( kg )

a  : is the acceleration ( m/s^2 )

We also know that the acceleration is denoted by the velocity ( v ) of an object as a function of time ( t ) with

a=\frac{v}{t}         Eqn. (2)

Now substituting Eqn. (2) into Eqn. (1) we have

F=m\frac{v}{t}\\ \\Ft=mv     Eqn. (3)

However since in Eqn. (3) the time-variable is present, as a result the left hand side (i.e. Ft is in fact the Impulse  J of the cart ), whilst the right hand side denotes the change in momentum of the cart, which by definition gives as the impulse. Also from the graph we can say that the Net Force is approximately ≈ 22N and t=4 sec (thus just before the cut-off time of the force acting).

Thus to find the Impulse we have:

J=Ft\\J=(22N)(4sec)\\J=88 kg m/s

So the impulse of the cart is J=88kg m/s

Then, we know that the cart is moving at v=10 m/s. Plugging in the values in Eqn. (3) we have:

(22N)(4sec)=(10m/s)m\\\\88=10m\\\\m=\frac{88}{10}\\ \\m=8.8kg

So the mass of the cart is m=8.8kg.

8 0
4 years ago
A 30-g bullet is fired with a horizontal velocity of 450 m/s and becomes embedded in block B, which has a mass of 3 kg. After th
Zolol [24]

Answer:

(a) The velocity of the bullet and B after the first impact is 4.4554 m/s.

(b) The velocity of the carrier is 0.40872 m/s.

Explanation:

(a) To solve the question, we  apply the principle of conservation of linear momentum as follows.

we note that the distance between B and C is 0.5 m

Then we  have

Sum of initial momentum = Sum of final momentum

0.03 kg × 450 m/s = (0.03 kg + 3 kg) × v₂

Therefore v₂ = (13.5 kg·m/s)÷(3.03 kg) = 4.4554 m/s

The velocity of the bullet and B after the first impact = 4.4554 m/s

(b) The velocity of the carrier is given as follows

Therefore from the conservation of linear momentum we also have

(m₁ + m₂)×v₂  = (m₁ + m₂ + m₃)×v₃

Where:

m₃ = Mass of the carrier = 30 kg

Therefore

(3.03 kg)×(4.4554 m/s) = (3.03 kg+30 kg) × v₃

v₃ = (13.5 kg·m/s)÷ (33.03 kg) = 0.40872 m/s

The velocity of the carrier = 0.40872 m/s.

3 0
3 years ago
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