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Ganezh [65]
2 years ago
11

a car with a mass of 2,00 kg travels a distance of 400 m as it moves from one stoplight to the next . as its fastest , the car t

ravels at 18 m/s. what is its kinetic energy at this point?
Physics
1 answer:
Semmy [17]2 years ago
7 0

Answer:

32400 J

Explanation:

K.E.=(1/2)(200)(18^2)

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ASAP ANSWER PLEASE WILL MARK BRAINLIEST
lisov135 [29]

Yes

Explanation:

It is a reasonable result obtained.

Error = true value - measured value

true value = 24.5

measured value = 24.2

Error =  24.5 - 24.2 = 0.3g

 The error reported in the reading is 0.3g

The reason why we had a disparity in the figures obtained from this measurement is primarily due to some erroneous scale.

The mixture at the end of the day is a solution.

We are expected to have the same mass but due to experimental or some form of random error introduced, we noticed a difference.

The value obtained is quite logical as we only had a deviation of 0.3g.

learn more:

Error brainly.com/question/2764830

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6 0
3 years ago
A tennis ball forgotten on the court after match is:
maw [93]
C is what i always have so ima go with C.
6 0
3 years ago
Read 2 more answers
Heat is transferred from molecules with more kinetic energy to molecules with _________kinetic energy.
Karolina [17]

Answer:

low

Explanation:

the higher the kinetic energy, the More the vibration of molecules, thus heat is more on the side with highly vibrating molecules

3 0
2 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the bui
soldi70 [24.7K]

Answer:

98.13m

Explanation:

Complete question

Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building

CHECK THE ATTACHMENT

From the figure, using trigonometry

Tan(θ ) = opposite/adjacent

Where Angle (θ )= 63°

Opposite= X = height of the building

Adjacent= 50 m

Then substitute the values we have

Tan(63)= X/50

1.9626= X/50

X= 1.9626 × 50

X= 98.13m

Hence, the height of the building is 98.13m

8 0
2 years ago
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