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Rzqust [24]
3 years ago
9

Highway transportation officials are trying to determine if the average speed on Archer road is above 45mph, the post speed limi

t. They took a sample of 50 cars. The sample mean was 44.9 and the standard deviation was 10. Find the test statistic.0.010.0707-0.01-0.0707
Physics
1 answer:
USPshnik [31]3 years ago
4 0

Answer:

Option D) -0.0707

Explanation:

We are given the following in the question:  

Population mean, μ = 45 mp

Sample mean, \bar{x} = 44.9

Sample size, n = 50

Sample standard deviation, s = 10

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{44.9 - 45}{\frac{10}{\sqrt{50}} } = -0.0707

Thus, the test statistic is

Option D) -0.0707

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Explanation:

30 minutes is 1800 seconds.

Power = energy / time

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P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

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The cheetah is one of the fastest-accelerating animals, because it can go from rest to 16.2 m/s (about 36 mi/h) in 2.4 s. If its
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<h2>Power of cheetah is 5576.85 W = 7.48 hp</h2>

Explanation:

Power is the ratio of energy to time.

Here we need to consider kinetic energy,

Mass, m = 102 kg

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Initial kinetic energy = 0.5 x Mass x Initial velocity² = 0.5 x 102 x 0² = 0 J

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Change in energy = Final kinetic energy - Initial kinetic energy

Change in energy = 13384.44 - 0

Change in energy = 13384.44 J

Power = 13384.44  ÷ 2.4 = 5576.85 W = 7.48 hp

Power of cheetah is 5576.85 W = 7.48 hp

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