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3 years ago

A 5 kg block of copper (specific heat capacity = 385 J/kg°C) at 20°C is given

Physics

1 answer:

monitta3 years ago

6 0

Answer:

$44^{\circ}C$

Explanation:

When heat energy is supplied to a substance, its temperature increases according to the equation:

$Q=mC\Delta T$

where

Q is the energy supplied

m is the mass of the substance

C is the specific heat capacity

$\Delta T$ is the increase in temperature

For the block of copper in this problem:

m = 5 kg

C = 385 J/kg°C

Q = 46,200 J

Therefore, the increase in temperature is

$\Delta T=\frac{Q}{mC}=\frac{46,200}{(5)(385)}=24^{\circ}C$

And since the initial temperature is 20°C, the final temperature will be

$T_f=20^{\circ}C+\Delta T=44^{\circ}C$

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A 10.0 L balloon contains helium gas at a pressure of 660 mmHg . What is the final pressure, in millimeters of mercury, of the h

Ksivusya [100]

Answer:

(a)= 264mmHg

(b)= 2000mmHg

(d)= 511.63mmHg

Explanation:

the question deals with boyles law, which states that the volume of a given mass of gas at constant temperature is inversely proportional to its pressure

V ∝ 1/P

P₁V₁ = P₂V₂

making V₂ as the subject of formular

P₂ = P₁V₁/ V₂

with a volume of 25.0L

P₂ = 660×10 / 25

= 264mmHg

with a volume of 3.30 L

P₂ = 660 × 10 / 3.30

= 2000mmHg

with a volume of 13900 mL

= 13.9L

P₂ =660× 10 / 13.9

474.82mmHg

with a volume of 12900 mL

P₂ =660×10 / 12.9

= 511.63mmHg

6 0

3 years ago

Carbon has six protons. Which model shows a neutral atom of carbon?

Anestetic [448]

Answer:

Explanation:

3 0

2 years ago

A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.

Brilliant_brown [7]

Answer:

Explanation:

velocity of proton v = 1.5 x 10³ i m /s

charge on proton e = 1.6 x 10⁻¹⁹ C

Let the magnetic field be B = Bx i + Bz k

force on charged particle ( proton )

F = e ( v x B )

2.06 x10⁻¹⁶ j = 1.6 x 10⁻¹⁹ [ 1.5 x 10³ i x ( Bx i + Bz k) ]

2.06 x10⁻¹⁶ j = - 1.6 x 10⁻¹⁹ x 1.5 x 10³ Bz j) ]

2.06 x10⁻¹⁶ = - 1.6 x 10⁻¹⁹ x 1.5 x 10³ Bz

Bz = - .8583

force on charged particle ( electron )

F = e ( v x B )

8.40 x10⁻¹⁶ j = -1.6 x 10⁻¹⁹ [ - 4.4 x 10³ k x ( Bx i + Bz k) ]

8.4 x10⁻¹⁶ j = 1.6 x 10⁻¹⁹ x 4.4 x 10³ Bx j ]

- 8.4 x10⁻¹⁶ = 1.6 x 10⁻¹⁹ x 4.4 x 10³ Bx

Bx = - 1.19

Magnetic field = - 1.19 i - .8583 k

magnitude = √ (1.19² + .8583²)

= 1.467 T

If it is making angle θ with x - axis in x -z plane

Tanθ = (.8583 / 1.19 )

36⁰ .

C )

v = - 3.7 x 10³j m /s

e = - 1.6 x 10⁻¹⁶ C

Force = F = e ( v x B )

= -1.6 x 10⁻¹⁹ [ -3.7 x 10³ j x ( Bx i + Bz k) ]

= - 1.6 x 10⁻¹⁹ x 3.7 x 10³ Bx k -1.6 x 10⁻¹⁹ x 3.7 x 10³Bzi ]

= 5.08 i - 7.04 k

Tanθ = 54 ° .

5 0

3 years ago

A man pushed a cabinet with a force of 200N. What is the mass of the cabinet that accelerates 4 m/s/s?

ELEN [110]

Answer:

$\boxed {\boxed {\sf 50 \ kg}}$

Explanation:

We are asked to find the mass of a cabinet, given the force and acceleration. According to Newton's Second Law of Motion, force is the product of mass and acceleration. The formula for this is:

$F= m \times a$

The force is 200 Newtons, but we should convert the units to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared, so the force of 200 Newtons is 200 kilogram meters per second squared.

The mass is unknown and the acceleration is 4 meters per second per second or 4 meters per second squared.

F= 200 kg*m/s²
a= 4 m/s²

Substitute the values into the formula.

$200 \ kg *m/s^2 = m \times 4 \ m/s^2$

We are solving for the mass, m, so we must isolate the variable. It is being multiplied by 4 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 4 m/s²

$\frac {200 \ kg *m/s^2}{4 \ m/s^2}= \frac{m \times 4\ m/s^2}{4 \ m/s^2}$