Question

A 5 kg block of copper (specific heat capacity = 385 J/kg°C) at 20°C is given

Answer 1

Answer:

$44^{\circ}C$

Explanation:

When heat energy is supplied to a substance, its temperature increases according to the equation:

$Q=mC\Delta T$

where

Q is the energy supplied

m is the mass of the substance

C is the specific heat capacity

$\Delta T$ is the increase in temperature

For the block of copper in this problem:

m = 5 kg

C = 385 J/kg°C

Q = 46,200 J

Therefore, the increase in temperature is

$\Delta T=\frac{Q}{mC}=\frac{46,200}{(5)(385)}=24^{\circ}C$

And since the initial temperature is 20°C, the final temperature will be

$T_f=20^{\circ}C+\Delta T=44^{\circ}C$