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tatyana61 [14]
3 years ago
11

A 5 kg block of copper (specific heat capacity = 385 J/kg°C) at 20°C is given

Physics
1 answer:
monitta3 years ago
6 0

Answer:

44^{\circ}C

Explanation:

When heat energy is supplied to a substance, its temperature increases according to the equation:

Q=mC\Delta T

where

Q is the energy supplied

m is the mass of the substance

C is the specific heat capacity

\Delta T is the increase in temperature

For the block of copper in this problem:

m = 5 kg

C = 385 J/kg°C

Q = 46,200 J

Therefore, the increase in temperature is

\Delta T=\frac{Q}{mC}=\frac{46,200}{(5)(385)}=24^{\circ}C

And since the initial temperature is 20°C, the final temperature will be

T_f=20^{\circ}C+\Delta T=44^{\circ}C

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