Newly occupied volume is 7.672L by N2 gas.
<u>Explanation:-
</u>
Given
V= 9.20 L, T(i) = T (f) = 294 K, P (i) = 0.959 atm, P (f) = 1.15 atm
To Find V (f)
Solution
According to the gas equation
PV= nRT
Where P=Pressure
V=Volume
n=No of moles
R=Universal gas constant
T=Temperature
Also we know the relation between pressure, volume and temperature as
PV/T = constant
![V(f)=[P(i) V(i) T(f)] \div[T(i) P(f)]](https://tex.z-dn.net/?f=V%28f%29%3D%5BP%28i%29%20V%28i%29%20T%28f%29%5D%20%5Cdiv%5BT%28i%29%20P%28f%29%5D)
Where P(i)V(i)/T(i) are the initial values of Pressure, Volume and Temperature.
P(f)V(f)/T(f) are the final values of Pressure, Temperature and Volume.
Substitute the known values in the equation we get
= 
=
= 7.672 L
Thus the final volume of the system is 7.672 L
Answer:
2.21% wt/v
Explanation:
The mass/volume percentage, %wt/v, is an unit of concentration used in chemistry defined as 100 times the ratio of the mass of solute in g (In this case, CaCl2 = 1.77g) and the volume of solution in mL = 80mL
The %wt/v of this solution is:
%wt /v = 1.77g / 80mL * 100
%wt/v = 2.21% wt/v
They should throw it away and use a different one
Chromium (Cr): 2, 8, 8, 6
Copper (Cu): 2, 8, 8, 11
Chromium+2 (Cr+2): 2, 8, 8, 4 (if the ion retains a positive charge then the amount of electrons will decrease)
Copper+2 (Cu+2): 2, 8, 8, 9
Manganese+2 (Mn+2): 2, 8, 8, 5
C) 10 grams
Explanation:
Potassium chlorate (KCIO₃) have a solubility in water at 70 °C of 30 grams in 100 grams of water.
If our solution have already 20 grams of potassium chlorate salt dissolved that means we need another 10 grams of potassium chlorate to reach the saturation point.
Learn more:
Potassium chlorate solubility in water
brainly.com/question/10140327
