Answer:
4.02g of Na2CO3⸱2H2O must be added completing the volume of the solution to 100mL
Explanation:
A 3%(w/v) solution contains 3g of solute (In this case, Na2CO3) in 100mL of solution.
Assuming we require 100mL of solution we must add 3g of Na2CO3. The reactant that is available is its dihydrate, with molar mass:
106g/mol + 2*MW H2O
106g/mol + 2*18g/mol = 142g/mol
That means the mass of Na2CO3.2H2O that must be added to prepare the solution is:
3g Na2CO3 * (142g/mol Na2CO3.2H2O / 106g/mol Na2CO3) =
<h3>4.02g of Na2CO3⸱2H2O must be added completing the volume of the solution to 100mL</h3>
since, a,b is an acid.. imposibble it is the answer
we left with c and d
while we can see that 'hyroxide' is a base
answer: C
Answer: The first question is chemical The second one is Physical
Explanation:
Answer:
Faster, and the substance will be a gas.
Explanation:
I'm quite not sure with it. But, I've tried my best. Since maybe the substance is liquid
The answer is C, good luck mate