Answer:
V₂ = 27 L
Explanation:
Given data:
Initial volume = 15 L
Initial temperature = 125 K
Final temperature = 225 K
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 15 L × 225K / 125 k
V₂ = 3375 L.K / 125 K
V₂ = 27 L
Answer:
A fund manager has portfolio worth $50 million with a beta of 0.87. The manager is concerned about the performance of the market over the next two months and plans to
use 3-month future contracts on the S&P 500 to hedge the risk.
Supersaturated solutions hold more of the solute at higher temperatures than they would at room temperature. Hence, the correct answer would be that the water would need to be heated to a higher temperature, which would give molecules and ions more kinetic energy, increasing solubility.
Generally, solubility increases with increase in temperature. At higher temperature, the kinetic energy of molecules in solution increase. Consequently, more of the molecules/ions of solutes collide more with each other and dissolve. At lower temperature, the molecules of the solutes crystalize out in solution.
More on solubility can be found here: brainly.com/question/22185953
Explanation:
to calculate theoratical yield...first we must calculate how much Sucrose moles we have..in order to to do so...we must calculate molar mass of sucrose.
molar mass of sucrose is 342.3 g/mol.
now we can calculate how many sucrose moles we have by dividing the mass with molar mass of sucrose
735g/(342.3g/mol)=2.147mol
theoratically...according to stoichiometry..every 1 mole of sucrose yields 4 moles of ethanol...so...
2.147mole yield 2.147*4mol=8.588mol
now we must calculate weight of that much ethanol..molar mass of ethanol is 46.07 g/mol...
so we can multiple moles by molar mass to obtain the weight 8.588mol*46.07g/mol=395.649g
but we only obtained 310.5g...so percentage we have is
78.47%
if there is trouble with molar mases I used....use what you calculated...
If my explanation is good enough...please mark it as brainliest.thanks
