Which element does not have the same number of electrons in its outermost shell as the other elements in its group?(1 point)

How many hydrogen (H) atoms are in 1 molecule of (NH4)2S ?

Alex73 [517]

Im not sure but it could be 4 (H)

3 0

2 years ago

PLEASE HELP, I WILL GIVE BRAINLIEST AND THANKS

jasenka [17]

Answer:

23dm

Explanation:

so you have to do 10g +13dm so the you have to times it by 3 three times

3 0

2 years ago

Two substances A and B, initially at different temperatures, are thermally isolated from their surroundings and allowed to come

Elden [556K]

Answer:

B

Explanation:

For solving this we need a heat balance

$Q_{a} = Q_{b}\\m_{a}*C_{a}*\Delta T_{a} = m_{b}*C_{b}*\Delta T_{b}$

By changing the corresponding relations, we have

$m_{a}*C_{a}*\Delta T_{a} = \frac{1}{2}m_{a}*4C_{a}*\Delta T_{b} \\\\\\$

By cancelling similar factor, we obtain

$\Delta T_{a} = 2 \Delta T_{b}\\\frac{\Delta T_{a}}{\Delta T_{b}} = 2\\$

Which means that the change of temperature in A is twice the change of B

3 0

2 years ago

A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.

adell [148]

Answer:

a) $V=4.3x10^3mL$

b) $V=4.3x10^6mm^3$

c) $\rho=1.5x10^5g/L$

Explanation:

Hello,

a) In this case, the given height in cm is:

$h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm$

And the radius in cm is:

$r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm$

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

$V=\pi (5.5cm)^2*45cm\\\\V=4.3x10^3cm^3=4.3x10^3mL$

b) In this case, the given height in mm is:

$h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm$

And the radius in mm is:

$r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm$

Thus, the volume in cubic millimeters is:

$V=\pi (55mm)^2*450mm\\\\V=4.3x10^6mm^3$

c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:

$\rho=\frac{m}{V}=\frac{6.54x10^5g}{4.3x10^3mL}*\frac{1000mL}{1L}\\ \\\rho=1.5x10^5g/L$

Best regards.

8 0

3 years ago

Which of the following describes a scenario in which the molecular geometry would have the smallest bond angle(s)? (A) four bond

maw [93]

Answer: The correct answer is "B" two bonding domains(or bonding pairs) or two non bonding domains(or lone pairs)

Explanation:

Molecular geometry/structure is a three dimensional shape of a molecule. It is basically an arrangement of atoms in a molecule.It is determined by the central atom, its surrounding atoms and electron pairs.According to VSEPR theory, there are 5 basic shapes of a molecule: linear, trigonal planar, tetrahedral, trigonal bipyramidal and octahedral.

A)Four bonding domains and zero non bonding domains: shape is tetrahedral and bond angle is 109.5°

B)Two bonding domains and two non bonding domains(lone pairs): shape is bent and bond angle is 104.5°

C)Three bonding domains and one non bonding domain: shape is trigonal pyramidal and bond angle is 107°

D)Two bonding domain and zero non bonding domain: shape is linear and bond angle is 107°

E)Two bonding domain and one non bonding domain: bent shape and bond angle is 120°

F)Three bonding domains and zero nonbonding domain: shape is trigonal planar and bond angle is 120°

Hence Two bonding domains and two non bonding domains have the smallest bond angle.

6 0

2 years ago