Sample of carbonate rock is a mixture of CaCO3 and MgCO3. The rock is Analyzed in a laboratory and the results are recorded in t
1 answer:
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Answer:
0.0400 g for the example given below.
Explanation:
pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.
- By definition,
.
- NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation:
.
- From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH:
.
- Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain:
.
- We also know that
. Take the antilog of both sides:
.
- Solve for the mass of NaOH:
.
Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:
<u>Answer:</u> The beta-particle is being released in the reaction and the nucleus is changing from to nitrogen.
<u>Explanation:</u>
Carbon-14 undergoes a radioactive decay by the process of beta-minus decay.
In beta-minus decay, a neutron gets converted to a proton and an electron.
The equation for the beta-minus decay of carbon-14 follows the reaction:
In this reaction beta-particle is being released carrying -1 charge. Another name for this particle is known as electron.
In this decay process, the nucleus is changing from carbon to nitrogen. The property of the nucleus is changing completely as number of protons is getting increased.