6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1
6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5
Answer:
56
Step-by-step explanation:
Complete question:
Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)
If z varies jointly with x, and y, this is expressed as;
z = kxy
If z=7 when x= 2, y= 2
7 = k(2)(2)
7 = 4k
k = 7/4
To get z when x= 4 and y = 8
z = kxy
z =7/4 (4)(8)
z = 7*8
z = 56
Hence the value of z is 56
Quadrant 1
Hope this helps!
Brainliest is much appreciated!
Answer:
q < 11
Step-by-step explanation:
Distribute the -3
23 - q > 12
Add q and subtract 12
q < 11
Answer:
Step-by-step explanation: