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3 years ago

Find the area of the rectangle as a single expression.

Mathematics

1 answer:

qwelly [4]3 years ago

7 0

Answer:

D) $15x^2 +6x-48$

Step-by-step explanation:

$Area \: of \: rectangle \\ = length \times width \\ = 3(x + 2) \times (5x - 8) \\ = (3x + 6) \times (5x - 8) \\ = 3x(5x - 8) + 6(5x - 8) \\ = 15 {x}^{2} - 24x + 30x - 48 \\ = 15 {x}^{2} + 6x - 48$

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Answer:

8.04 units

Step-by-step explanation:

By Pythagoras Theorem:

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Answer:

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Answer:

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Step-by-step explanation:

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A doctor at a local hospital is interested in estimating the birth weight of infants. How large a sample must she select if she

Nataly_w [17]

Answer:

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

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That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

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A sample of n is needed, and n is found when M = 4. So

$M = z\frac{\sigma}{\sqrt{n}}$

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$\sqrt{n} = \frac{1.96\sqrt{\sigma}}{4}$

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$n = (\frac{1.96\sqrt{\sigma}}{4})^2$

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

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Strike441 [17]

Answer:

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