Answer:
tan(x-y) = -16/63
Step-by-step explanation
Tan(x-y) if cscx=13/5 and coty=4/3
Given
coty = 4
1/tany = 4/3
Cross multiply
tan y = 3/4
Also since cscx = 13/5
1/sinx = 13/5
sinx = 5/13
Since sinx = opp/hyp
opp = 5
hyp = 13
Get the adjacent
hyp² = opp²+adj²
13² = 5²+adj²
adj² = 13² - 5²
adj² = 169 - 25
adj² = 144
adj = 12
cosx = adj/hyp
cosx = 12/13
tanx = sinx/cosx
tanx = (5/13)/(12/13)
tanx = 5/13 * 13/12
tan x = 5/12
tan(x-y) = tanx - tany/1+tanxtany
tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)
tan(x-y) = (5-9/12)/1+5/16
tan(x-y) = -4/12/(21/16)
tan(x-y) = -1/3 * 16/21
tan(x-y) = -16/63
There is a given point (10,3) this shows that when the width (X) is 10, the height (Y) is 3.
On the left side of the graph, they show an equation for the height Hw as being the constant over w ( width).
Using the given point solve for the constant.
Replace Hw with 3 and w with 10:
3 = Constant/10
Solve for the constant by multiplying both sides by 10:
Constant = 3 x 10
Constant = 30
The answer is B.
Answer:
1
Step-by-step explanation:
5x2 is 10 subtract that and add it to 6 which gives you -4 then you do -4/-4 which is 1
Answer:
B. y=3(x-1)2 + 3
Step-by-step explanation:
Given that
vertex of the parabola is at the point (1,3)
let's verify, if the option B is the correct equation of the parabola.
comparing to standard equationof parabola (standard quadratic equation), we get
to find the vertex we use formula for x- coordinate as
to find y put x=1 in the Eq1, we get
vertex =(x,y) = (1, 3)
thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified
Answer:
(0.4,1)
Step-by-step explanation:
I hope that this is for homework and not a quiz or test.
Since we already know the value of y which is 1, we can substitute it into the equation above it.
-5x+3=1
-5x=-2
x=2/5=0.4
So in (x,y) format (0.4,1)