Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
Answer:
18
Step-by-step explanation:
25 + 47 = 72
72 ÷ 4 = 18
I believe it would be 6 due to the radius being a half of the actual circumfrence
Answers:
1. 5(x-6)
2. k-9
3. 10x + 5
4. the quotient of some number and six
5. the quotient of three times a number and five
6. x^5
Because we know the area in terms of paint flow, and paint flow in terms of time, we can substitute p(t) for p in the A(p) equation.
A(p(t)) = A(t) = <span>π * (5t)^2 (assuming it's squared for the A(p).
B: 314 units^2
If A(p) = </span>πp2 (instead of p^2), then A(t) = 10πt
B: 31.4 units^2
