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monitta
3 years ago
6

What quantity of energy, in joules, is required to raise the temperature of 425 g of tin from room temperature, 25.0 °C, to its

melting point, 231.9 C, and then melt the tin at that temperature? (The specific heat capacity of tin is 0.227 J/g K, and the heat of fusion of this metal is 59.2 Jig) Energy required
Chemistry
1 answer:
Rama09 [41]3 years ago
6 0

Answer:

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is 45.249 kiloJoules.

Explanation:

Mass of the tin ,m= 425 g

Heat capacity of the tin ,c= 0.227 J/g K

Initial temperature of the tin ,T_1= 25.0 °C = 298.15 K

Final temperature of the tin, T_2= 231.9 °C = 505.05 K

Let the heat required to change the temperature of tin from 298.15 K to 505.05 K be Q.

Q=mc\times (T_2-T_1)

=425 g\times 0.227 J/g K\times (505.05K - 298.15 K)=19,960.68 J=19.961 kJ

Heat required to melt tin at 505.05 K be Q'

The heat of fusion of tin metal =\Delta H_{fus}=59.2 J/g

Q'= m\times \Delta H_{fus}=425 g\times 59.2 J/g=25,287.5 J=25.288 kJ

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is:

= Q+Q' =  19.961 kJ + 25.288 kJ = 45.249 kJ

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Which of the following elements is most likely to form an ion that will then form an ionic bond with an ion of a Group 1A elemen
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3 years ago
Which atomic orbitals overlap to form the carbon-carbon σ and π bonding molecular orbitals of ethene, H2C=CH2?
Zanzabum

Answer:

σ -> 2sp²

π -> 2p

Explanation:

The carbon has valence shell 2s 2p, and, both of them make 3 σ bonds and 1 π bond. The π bond only occurs in multiple bonds.

The σ bonds happen at the hybrids orbitals, which are orbitals formed by the association of the pure orbitals (s, p, d, f). The hybridization occurs to make possible to the atom to do the bonds because the electrons need to be isolated in it.

On the other hand, the π bonds only occur at pure orbitals. The subshell s only has 1 orbital, and the subshell p has 3 orbitals. So, because there are 3 σ bonds, it's necessary 3 hybrids orbitals (1 of s + 2 of p).

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The electron configuration of a neutral atom is 1s22s22p63s2. Write a complete set of quantum numbers for each of the electrons.
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Answer:

The four quantum number for each electron will be:

1s^{2}

n=1;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2s^{2}

n=2;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2p^{6}

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3s^{2}

n=3;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

Explanation:

As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.

Number of electrons =12

Atomic number = 12

Element : Magnesium

The principal shell is represented by "n"

i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0

The two electrons in s subshell will have either plus half or minus half spin quantum number

ii) for "p" subshell the value for l =1

thus m = 0 or +1 or -1

The two electrons in each orbital will have either plus half or minus half spin quantum number

8 0
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