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Mrrafil [7]
3 years ago
12

A given hydrocarbon is converted completely to carbon dioxide and water, and equal numbers of moles of co2 and h2o are produced.

the hydrocarbon would be
Chemistry
1 answer:
Sauron [17]3 years ago
4 0
X moles of CO₂, and x moles of H₂O

CxH2x + 3x/2 O₂ -------> xCO₂ + xH₂O

CxH2x or CnH2n ----> ALKENE ( hydrocarbon with double bond)

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The chemical equation below shows the photosynthesis reaction. 6co2 6h2o right arrow. c6h12o6 6o2 the molar mass of carbon dioxi
iogann1982 [59]

The moles of water are used in the given reaction between CO₂ & H₂O is 12 moles.

<h3>How do we calculate mass from moles?</h3>

Mass of any substance will be calculated by using their moles as:

n = W/M , where

W = given or required mass

M = molar mass

Given chemical reaction is:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Moles of 528 g of CO₂ = 528g / 44.01g/mol = 11.99 moles

From the stoichiometry of the reaction, it is clear that:

6 moles of CO₂ = reacts with 6 moles of H₂O

So, 11.99 moles of CO₂ = reacts with 11.99 = 12 moles of H₂O

Hence option (a)is correct i.e. 12 moles.

To know more about moles, visit the below link:

brainly.com/question/15373263

5 0
2 years ago
Hydrogen bond is an example for? (PLEASE HELP!)
zlopas [31]

Answer:

b)

Explanation:

hydrogen bond is a form of dipole-dipole interaction but with more unique properties

3 0
2 years ago
A 0.307-g sample of an unknown triprotic acid is titrated to the third equivalence point using 35.2 ml of 0.106 m naoh. calculat
Jet001 [13]
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions.  So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3. 
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole.  So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
6 0
3 years ago
If 1.20 moles of an ideal gas occupy a volume of 18.2 l at a pressure of 1.80 atm, what is the temperature of the gas, in degree
scoundrel [369]

We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚<span>C</span>

6 0
3 years ago
You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain
____ [38]

6.9 Sleps 1. (8)(13) = 15 2. 104/15 = 15/15 3. 6.93333333 4. 6.9 Sleps

6 0
3 years ago
Read 2 more answers
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