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12345 [234]
3 years ago
10

Which of the following is an example of a saturated hydrocarbon?

Chemistry
2 answers:
MakcuM [25]3 years ago
4 0
C. Ethyne. Hope this helped :)
KIM [24]3 years ago
3 0

Answer: B. Heptane

Explanation:

Saturated hydrocarbons are defined as the hydrocarbons in which a single bond is present between carbon and carbon atoms. they are known as alkanes. The general formula for these hydrocarbons is C_nH_{2n+2}

Unsaturated hydrocarbons are defined as the hydrocarbons which have double or triple covalent C-C bonds. They are known as alkenes and alkynes respectively. The general formula for these hydrocarbons is C_nH_{2n} and C_nH_{2n-2}

A. Nonyne is an alkyne with 9 carbon atoms with molecular formula of C_9H_{16}

B. Heptane  is an alkane with 7 carbon atoms with molecular formula of C_7H_{16}

C. Ethyne is an alkyne with 2 carbon atoms with molecular formula of C_2H_{2}.

D. Hexene is an alkene with 6 carbon atoms with molecular formula of C_6H_{12}

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A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 60.00 gram sample of the alcohol p
marin [14]

Answer:

C_2H_6O

Explanation:

The first step is the <u>calculation of the moles</u> of H_2O and CO_2, so:

114.6~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=2.6~mol~of~CO_2

70.44~g~H_2O\frac{1~mol~H_2O}{18~g~H_2O}=~3.9~mol~H_2O

Now, in 1 mol of CO2 we have 1  mol of C and in 1 mol of H_2O we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to <u>calculate the grams of C and O</u> and then do the <u>substraction</u> form the initial amount, so:

2.6~mol~CO_2\frac{1~mol~C}{1~mol~CO_2}\frac{12~g~C}{1~mol~C}=31.25~g~of~C

3.9~mol~H_2O\frac{2~mol~H}{1~mol~H_2O}\frac{1~g~H}{1~mol~H}=7.82~g~of~H

Total~grams=~31.25~+~7.82=39.08~g

grams~of~O=60.00~g-~39.08~g=20.92~g~of~O

Now we can <u>convert the grams</u> of O to moles, so:

20.92~g~of~O\frac{1~mol~O}{16~g~O}=1.30~mol~O

The next step is to divide all the mol values by the <u>smallest one</u>:

O=\frac{1.30~mol~O}{1.30~mol~O}=~1

C=\frac{2.6~mol~C}{1.30~mol~O}=~2

H=\frac{7.82~mol~H}{1.30~mol~O}=6

Therefore the formula is C_2H_6O

6 0
3 years ago
How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?
poizon [28]

Answer:

9.57 mol.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

<em>M = (no. of moles of solute)/(V of the solution (L)).</em>

<em></em>

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>

5 0
3 years ago
Given the equation representing a system at equilibrium in a sealed, rigid container:
LenaWriter [7]

Answer:

Choice 1. "HI to increase".

Explanation:

I found out the hard way.

4 0
3 years ago
Read 2 more answers
The pH of a solution is 8. Some hydrochloric acid is added to the solution. Suggest the pH of the solution after mixing. pH=....
Molodets [167]

Answer:

Probably around 6 because the ph of hydrochloric acid is 3

Explanation:

3 0
3 years ago
The water cycle would not be possible without ______ and ________.
ipn [44]

Answer:

I think it's 4

Explanation:

but I don't really remember the water cycle

4 0
3 years ago
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