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Drupady [299]
3 years ago
10

Consider the following cyclic process carried out in two steps on a gas. Step 1: 44 J of heat is added to the gas, and 20. J of

expansion work is performed. Step 2: 61 J of heat is removed from the gas as the gas is compressed back to the initial state. Calculate the work for the gas compression in Step 2.
Physics
1 answer:
notka56 [123]3 years ago
3 0

Answer:37 J

Explanation:

Given

Step :1

Heat added Q=44 J

Work done=-20 J

\Delta E_1=Q+W=44-20=24 J

Step :2

Heat added Q=-61 J

work done W_2

\Delta E_2=Q+W_2

\Delta E_2=61+W_2

\Delta E_1+\Delta E_2=0

as the process is cyclic

44-20-61+W_2=0

W_2=37 J

work done in compression is 37 J

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3 years ago
Is it possible for an object to be in motion without any external force applied? justify
Rudiy27
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By the time Newton came along, the prevailing theory of motion—formulated by Aristotle—was nearly two thousand years old. It stated that if an object is moving, some sort of force is required to keep it moving. Unless that moving thing is being pushed or pulled, it will simply slow down or stop. Right?
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8 0
3 years ago
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5 0
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Simora [160]

Answer:

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