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3 years ago

Why do you think energy usage is different at different times of the day

Physics

2 answers:

g100num [7]3 years ago

7 0

People are asleep at 3 am so energy would be less then.

OverLord2011 [107]3 years ago

3 0

Peak usage times, the more applicances that are used, the larger the pull and demand for energy. Therefore creating a larger load. Which in term causes more energy to be used. Hope that helped

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A pendulum of mass 5.0 kg hangs in equilibrium. A frustrated student walks up to it and kicks the bob with a horizontal force of

Phoenix [80]

Answer:

The length is $L = 6.206m$ and the angle is $\theta = 37.752^o.$

Explanation:

The period $T$ of the pendulum is related to its length $L$ by

$T = 2\pi \sqrt{\dfrac{L}{g} },$

where $g =9.8m/s^2$ is the acceleration due to gravity.

Solving for $L$ we get

$L = \dfrac{T^2g}{4\pi^2}$

putting in $T =5.0s$ and $g =9.8m/s^2$ we get:

$L = \dfrac{(5.0s)^2*9.8m/s^2}{4\pi^2}$

$\boxed{L = 6.206m.}$

There are two forces acting on the pendulum: The gravitational force $mg$ and the $F = 30N$ student's force. Therefore, the angular displacement $\theta$ that these forces give is

$sin(\theta ) = \dfrac{F}{mg}$

$\theta = sin^{-1}( \dfrac{F}{mg})$

putting in $F =30N$ , $m =5.0kg$ , and $g =9.8m/s^2$ we get

$\theta = sin^{-1}( \dfrac{30N}{5.0kg*9.8m/s^2})$

$\boxed{\theta = 37.752^o.}$

4 0

3 years ago

Imagine you are on an airplane. Your plane has flown from 30 degrees North to 42 degrees North. How far have you flown?

ycow [4]

The answer to your question is 12 degrees because you subtract 42 degrees minus 30 degrees to get 12 degrees

7 0

3 years ago

How does an air mattress protect a stunt person landing on the ground after a stunt?

Fudgin [204]

Answer:

a) It reduces the kinetic energy loss of the stunt person.

6 0

2 years ago

A baseball has a momentum of 6.0 kg.m/s south and mass of 0.15kg. What’s the baseballs velocity?

Mashcka [7]

Answer:

<em>v=40 m/s south</em>

Explanation:

<u>Momentum </u>

It's a physical magnitude that measures the product of the mass by the velocity of a particle. Its units in the International System is kg.m/s and the formula is

$p=m.v$