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Which of the following is a harmful effect of oil spills? (A)Migration of large schools of fish (B)Changes in sea level (C)Plant

kotegsom [21]

C is your answer to the question

4 0

2 years ago

Read 2 more answers

An archer shoots an arrow with a mass of 45.0 grams from bow pulled

Sladkaya [172]

Answer:

The force the archer need to pull in order to achieve the height is approximately 101.8 N

Explanation:

By energy conservation principle, puling an elastic bow with a force, for a given distance, performs work which is converted to the potential energy of the arrow at height

The given parameters are;

The mass of the arrow, m = 45.0 grams = 0.045 kg

The distance the elastic bow is pulled, d = 65.0 cm = 0.65 m

The height at which the arrow is reaches, h = 150.0 meters

Let 'F', represent the force the archer need to pull in order to achieve the height

Work done, W = Force × Distance moved in the direction of the force

Therefore;

The work done in pulling the arrow, W = F × d

By energy conservation, we have;

The work done in pulling the arrow, W = The potential energy gained by the arrow, P.E.

W = P.E.

The potential energy gained by the arrow, P.E. = m·g·h

Where;

m = The mass of the arrow

g = The acceleration due to gravity = 9.8 m/s²

h = The height the arrow reaches

∴ by plugging in the values, P.E. = 0.045 kg ×9.8 m/s² × 150 m = 66.15 J

W = F × d = F × 0.065 m

Also, W = P.E. = 66.15 J

∴ W = F × 0.065 m = 66.15 J

F × 0.065 m = 66.15 J

F = 66.15 J/(0.65 m) = 1323/13 N ≈ 101.8 N

The force the archer need to pull in order to achieve the height, F ≈ 101.8 N.

3 0

2 years ago

Explain what voltage,current, resistance are and how they relate to Ohms law. Then give examples

SOVA2 [1]

Voltage is the difference in charge between two points.
Current is the rate the charge flows
Resistance is the tendency a material has to resist the flow of charge (current)
Combining voltage resistance and current Ohm developed the formula
V (Voltage)= I (Current) x R (Resistance)

3 0

3 years ago

A 50-g chunk of 80 degrees C iron is dropped into a cavity in a very large block of ice at 0 degrees C. Show that 5.5 g of ice w

Alenkasestr [34]

Answer:

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

$Q = mc\Delta T$

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

$\Delta T =$ Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

$Q = mc\Delta T$

$Q = 50*0.11*(80-0)$

$Q = 440cal$

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

$Q_2 = mL = 80*m$

How Q_1=Q_2, so

$80m=440$

$m=\frac{440}{80}$

$m = 5.5g$

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

7 0

3 years ago

An interference pattern is produced by light with a wavelength 520 nm from a distant source incident on two identical parallel s

Goshia [24]

Answer:

1) θ = 0.00118 rad, 2) θ = 0.00236 rad , 3) I / I₀ = 0.1738, 4) I / Io = 0.216

Explanation:

In the double-slit interference phenomenon it is explained for constructive interference by the equation

d sin θ = m λ

1) the first order maximum occurs for m = 1

sin θ = λ / d

θ = sin⁻¹ λ / d

let's reduce the magnitudes to the SI system

λ = 520 nm = 520 10⁻⁹ θ = 0.00118 radm

d = 0.440 mm = 0.440 10⁻³ m ³

let's calculate

θ = sin⁻¹ (520 10⁻⁹ / 0.44 10⁻³)

θ = sin⁻¹ (1.18 10⁻³)

θ = 0.00118 rad

2) the second order maximum occurs for m = 2

θ = sin⁻¹ (m λ / d)

θ = sin⁻¹ (2 5¹20 10⁻⁹ / 0.44 10⁻³)

θ = 0.00236 rad

3) To calculate the intensity of the interference spectrum, the diffraction phenomenon must be included, so the equation remains

I = I₀ cos² (π d sin θ /λ ) sinc² (pi b sin θ /λ )

where the function sinc = sin x / x

and b is the width of the slits

we caption the values

x = π 0.310 10⁻³ sin 0.00118 / 520 10⁻⁹)

x = 2.21

I / I₀ = cos² (π 0.44 10⁻³ sin 0.00118 / 520 10⁻⁹) (sin (2.21) /2.21)²

remember angles are in radians

I / I₀ = cos² (3.0945) [0.363] 2

I / I₀ = 0.9978 0.1318

I / I₀ = 0.1738

4) the maximum second intensity is

I / I₀ = cos² (π d sinθ / λ) sinc² (πb sin θ /λ)

x =π 0.310 10⁻³ sin 0.00236 / 520 10⁻⁹)

x = 4.41

I / Io = cos² (π 0.44 10⁻³ sin 0.00236 / 520 10⁻⁹) (sin 4.41 / 4.41)²

I / Io = cos² 6.273 0.216

I / Io = 0.216

.

7 0

2 years ago

I will give brainliest if you sub and stay subbed to JD Outdoors & Gaming​

I will give brainliest if you sub and stay subbed to JD Outdoors & Gaming