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Bingel [31]
4 years ago
9

How much concentrated solution would you take to prepare 1.15 L of 0.105 M HNO3 by mixing with water?

Chemistry
1 answer:
nydimaria [60]4 years ago
7 0

Answer:

7.67578 ml

Explanation:

assuming the missing information

Conc. of nitric acid = 70.3% by mass

density =1.41 g/ml

Now, moles of HNO3 required = final volume× final conc.

= 1.15×0.105= 0.12075 mol

Mass of HNO3 required = moles×molar mass of HNO3

= 0.12075×63.01=7.6084575 g

mass of solution = 100/70.3 of 7.6084575

=10.82284 g

therefore, volume of the solution = mass/density

= 10.82285/1.41

= 7.67578 ml

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