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2 years ago

What evidence lead rutherford to propose that the atom had a nucleus?

Chemistry

1 answer:

BigorU [14]2 years ago

5 0

Answer:

When he shot radiation through gold foil, some of the radiation shot back, some went directly through, and some slight angled off.

Explanation:

He knew that the radiation that had gone all the way through had not hit anything.

He knew that the radiation that came directly back must have hit a big nucleus.

He knew that the radiation that angled slightly off must have hit a smaller, orbiting particle (electrons).

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Which of the following transfers carbon from the nonliving environment to the living environment?

ludmilkaskok [199]

Decomposing because it was being eaten to be decomposed into particles.<span />

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3 years ago

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6. What causes the phases of the moon?

lawyer [7]

Answer:

The rotation of the Earth.

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2 years ago

Use the definition of molarity to calculate the concentration of 12.34 g of CaSO4 completely dissolved in water, with a solution

Ede4ka [16]

Answer:

[CaSO₄] = 36.26×10⁻² mol/L

Explanation:

Molarity (M) → mol/L → moles of solute in 1L of solution

Let's convert the volume from mL to L

250 mL . 1L/1000 mL = 0.250L

We need to determine the moles of solute. (mass / molar mass)

12.34 g / 136.13 g/mol = 0.0906 mol

M → 0.0906 mol / 0.250L = 36.26×10⁻² mol/L

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3 years ago

Which best describes nuclear fission? A nucleus spontaneously splits and absorbs energy. Two nuclei spontaneously combine and ab

Maurinko [17]

Answer:

A nucleus collides with a neutron and splits, releasing energy.

Explanation:

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2 years ago

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A chemist titrates 150.0 mL of a 0.2653 M carbonic acid (H2CO3) solution with 0.2196 M NaOH solution at 25 °C. Calculate the pH

xxTIMURxx [149]

Answer:

9.3

Explanation:

This is long and complicated so get ready

We are going to use the conjugate base of carbonic acid with water to make carbonic acid and OH- (Na is simply a spectator ion and is irrelavent here)

Let the conjugate base be A- and Carbonic acid be HA

A- + H20 ⇄ HA + OH-

To find the concentration of A- we must find the concentration of the reactants given. We know this will be equal because it is a strong base and all of it disassociates.

to get moles of acid we take the concentration and multiply by liters to cancel

.2653 x .150 = .039795 mol HA

Because it is at equivalence point we know the moles will be equal. We are given the concentration so we only have to solve for liters

We plug it into the equation and found: .181 L

Now use moles and combined volums to fins concentrarion which is .120 M

Now plug that use the Ka converted to Kb to find the cincentrations of HA and OH-

Ka is (10^-3.60) = 2.4E-4

Kb x Ka is 10^-14

Kb = 3.98E-11

Now we know Kb = [HA] [OH] / [A-]

Solve for this through algebra by using x for the values you dont know

youll find x^2 = 3.3E-10

X = 1.8 E -5

this is the OH- concentration

-log [oh] = pOH

pOH = 4.73

We know 14-pOH = ph so pH= 9.3

6 0

3 years ago