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2 years ago

What evidence lead rutherford to propose that the atom had a nucleus?

Chemistry

1 answer:

BigorU [14]2 years ago

5 0

Answer:

When he shot radiation through gold foil, some of the radiation shot back, some went directly through, and some slight angled off.

Explanation:

He knew that the radiation that had gone all the way through had not hit anything.

He knew that the radiation that came directly back must have hit a big nucleus.

He knew that the radiation that angled slightly off must have hit a smaller, orbiting particle (electrons).

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jasenka [17]

Ok, I will help you answer but it is very hard to read could you enlarge it first?

Thanks!

5 0

3 years ago

How do you do this?

Alona [7]

It would be Atom 2 because the proton and neutron are both nine and the election is 8 which is -1 to nine

7 0

3 years ago

Calculate the area of a 3.0 inch by 5.0 inch index card in square millimeters (mm). (You can look up the formula for the area of

meriva

Answer:

The area of the given rectangular index card = 9677.4 mm²

Explanation:

Area is defined as the space occupied by a two dimensional shape or object. The SI unit of area is square metre (m²).

The area of a rectangle (A) = length (l) × width (w)

Given dimensions of the rectangle: Length (l) = 5.0 inch, Width (w) = 3.0 inch

Since, 1 inch = 25.4 millimetres (mm)

Therefore, l = 5 × 25.4 = 127 mm, and w = 3 × 25.4 = 76.2 mm

Therefore, the area of the given rectangular index card = A= l × w = 127 mm × 76.2 mm = 9677.4 mm²

5 0

3 years ago

The following question appears on a quiz: ""You fill a tank with gas at 60Â°C to 100 kPa and seal it. You decrease the temperatu

dusya [7]

Answer: The final pressure will decrease ad the value is 85 kPa

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=100kPa\\T_1=60^0C=(60+273)K=333K\\P_2=?\\T_2=10^0C=(10+273)K=283K$

Putting values in above equation, we get:

$\frac{100kPa}{333K}=\frac{P_2}{283K}\\\\P_2=85kPa$

Hence, the final pressure will decrease ad the value is 85 kPa

8 0

3 years ago

Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

goblinko [34]

The balanced equation for

Ca(OH)2 + H3PO4→ Ca3(PO4)2 + H2O is

3 Ca(OH)2 +2 H3PO4→ Ca3(Po4)2 + 6 H2O

3 moles of Ca(OH)2 reacted with 2 moles of H3PO4 to form 1 mole of Ca3(PO4)2 and 6 moles of H2O

6 0

3 years ago

Read 2 more answers