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Vladimir79 [104]
3 years ago
10

90 grams of NaNO3 were added to solution at 10 degrees Celsius. What type of solution was formed?

Chemistry
1 answer:
vichka [17]3 years ago
4 0

Answer:

friend me on here and imma send you the link Explanation:

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n the laboratory, two forms of sodium phosphate will be available (the monobasic monohydrate NaH2PO4·H2O, F.W. = 137.99 g/mol, a
const2013 [10]

Answer:

The compound you will use is the Dibasic phosphate

Explanation:

Simple phosphate buffer is used ubiquitously in biological experiments, as it can be adapted to a variety of pH levels, including isotonic. This wide range is due to phosphoric acid having 3 dissociation constants, (known in chemistry as a triprotic acid) allowing for formulation of buffers near each of the pH levels of 2.15, 6.86, or 12.32. Phosphate buffer is highly water soluble and has a high buffering capacity,

In this case the most efficient way is to disolve the dibasic compound which in the reaction with the water will form the monobasic phosphate.

To make the buffer you have to prepare the amount of distillate water needed, disolve the dibasic phospate, and then adjust with HCl or NaOH depending on the pH needed.

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3 years ago
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3 0
3 years ago
Morphine sulfate given intravenously, by itself, at once, is known as:__________a. none of the answers are correct b. iv push c.
Travka [436]

Morphine sulfate given intravenously, by itself, at once, is known as push.

<h3>What is Morphine ?</h3>

A member of the opiate family of painkillers, morphine is naturally present in opium, a dark-brown substance found in poppies (Papaver somniferum). Morphine can be given orally, sublingually, inhaled, injected into a muscle, injected under the skin, intravenously, into the area around the spinal cord, transdermally, or as a rectal suppository. It causes analgesia and modifies perception and emotional reaction to pain by acting directly on the central nervous system (CNS). With repeated use, tolerance and reliance could develop on both a physical and psychological level. It is widely used for pain from myocardial infarction, kidney stones, and labor pain and can be taken for both acute and chronic pain.

To learn more about  Morphine  from the given link:

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6 0
1 year ago
1. Using the balanced equation, answer the following questions:
nalin [4]

Answer:

                     a)  2.53 × 10²³ molecules of O₂

                     b)  31.90 g of KCl

Explanation:

                  The balance chemical equation for given decomposition reaction is as follow;

                                   2 KClO₃ → 2 KCl + 3 O₂

<h3>Part 1:</h3>

Step 1: <u>Calculate Moles for given amount of KClO₃;</u>

                    Moles  =  Mass / M.Mass

                    Moles  =  34.35 g / 122.55 g/mol

                    Moles  =  0.280 moles of KClO₃

Step 2: <u>Find out  moles of O₂ produced;</u>

According to eq,

                  2 moles of KClO₃ produces  =  3 moles of O₂

So,

            0.280 moles of KClO₃ will produce  =  X moles of O₂

Solving for X,

                    X  =  0.280 mol × 3 mol / 2 mol

                     X =  0.42 moles of O₂

Step 3: <u>Calculate No. of Molecules of O₂ as,</u>

No. of Molecules  =  Moles × 6.022 × 10²³

No. of Molecules  =  0.42 mol × 6.022 × 10²³ molecules/mol

No. of Molecules  =  2.53 × 10²³ molecules of O₂

<h3>Part 2:</h3>

Step 1: <u>Calculate Moles for given amount of KClO₃;</u>

                    Moles  =  Mass / M.Mass

                    Moles  =  52.53 g / 122.55 g/mol

                    Moles  =  0.428 moles of KClO₃

Step 2: <u>Find out  moles of KCl produced;</u>

According to eq,

                  2 moles of KClO₃ produces  =  2 moles of KCl

So,

            0.428 moles of KClO₃ will produce  =  X moles of KCl

Solving for X,

                    X  =  0.428 mol × 2 mol / 2 mol

                     X =  0.428 moles of KCl

Step 3: <u>Calculate Mass of KCl as;</u>

                         Mass  =  Moles × M.Mass

                         Mass  =  0.428 mol × 74.55 g/mol

                         Mass  =  31.90 g of KCl

6 0
3 years ago
What specifically determines how much energy is available in a molecule
irina1246 [14]
Possibly the amount of electrons and energy levels in which the electrons reside

5 0
3 years ago
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