Answer:
the hydrogen atom of one water molecule and the lone pair of electrons on an oxygen atom of a neighboring water molecule.
Answer:
B
Explanation:
its upside down but I'm 99% sure
moles = molarity * 1000/volume
7*1000/14.44= 484.76
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Explanation:
AgNO₃+Na₃(PO₄) → Ag₃(PO₄) + NaNO₃
To balance this chemical equation, we can adopt a simple mathematical approach through which we can establish simple and solvable algebraic equations.
aAgNO₃ + bNa₃PO₄ → cAg₃PO₄ + dNaNO₃
a, b, c and d are the coefficients needed to balance the equation.
Conserving Ag: a = 3c
N: a = d
O: 2a + 4b = 4c + 2d
Na: 3b = d
P: b = c
let a = 1; d = 1
b = 
c = 
Multiplying through by 3:
a = 3, b = 1, c = 1 and d = 3
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Learn more:
Balanced equation
brainly.com/question/5964324
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When PH = ㏒(H^+)
[H+] = 10^-3.67
[H+] = 2.14x 10^-4
so according to the reaction equation:
HF ↔ H^+ + F^-
at equilibrium X-(2.14x10^-4) (2.14x10^-4) (2.14x10^-4)
by substitution in Ka formula:
Ka = [H+][F]-/[HF]
6.8x10^-4 = (2.14x10^-4)*(2.14x10^-4) /(X-2.4x10^-4)
X-2.4x10^-4 = (4.58x10^-8)* (6.8x10^-4)
∴X = 2.4x10^-4
∴[HF] = X- (2.14x10^-4)= (2.4x10^-4)-(2.14x10^-4) = 2.6 X 10^-5