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LuckyWell [14K]
3 years ago
15

The radius of a barium atom is 2.22e-10 m what is its radius in angstroms

Chemistry
2 answers:
nadya68 [22]3 years ago
8 0

Solution:

Angstroms is defined as a unit of length equal to one hundred-millionth of a centimeter, 10–10 meter, used mainly to express wavelengths and inter atomic distances.

Therefore,

1 angstroms=10 -10 m  

2.22*10^ -10 m=2.22*10 -10 /10 -10  

=2.22 angstroms  


Arlecino [84]3 years ago
6 0

Angstroms is a unit used for 10^-10 It means that one meter will have 10^10 Angstroms or 1 Angstroms = 10^-10 meters the given radius of barium atom is 2.22 X10^-10 m This will be equal to 2.22 Angstroms.

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D. or C. I think it is more D. than anything else

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Consider the structures of vinegar and triglyceride and draw in any bond dipoles that exist in the molecules above using a dipol
bagirrra123 [75]

Answer:

Given molecules are vinegar and triglycerides.

Explanation:

The dipole is a vector quantity and it is heading from less electronegative atom to more electronegative atom in a polar covalent bond.

The structures and the bond dipoles in the given molecules are shown below:

5 0
3 years ago
Calculate the concentration in mol/L, M, of an aqueous sugar solution with a concentration of 23.5% (w/w) and density of 1.005 g
Temka [501]

Answer:

The concentration in mol/L is 0.683M

Explanation:

23.5% (w/w)

This data means that in 100 g of solution, we have 23.5 grams of solute.

From this point, we can calculate the moles of sugar.

Moles = Mass / Molar mass

Moles = 23.5 g /342.30 g/m

Moles = 0.068 moles

Density data make us know, the volume of our solution.

solution δ = solution mass / solution volume

δ = 1.005 g/mL = 100 g /  solution volume

solution volume = 100g / 1.005 g/ml

solution volume = 99.5 mL

In conclusion, 0.068 moles are in 99.5 mL

Molarity (M) is mol/L

Let's convert 99.5 mL in L

99.5 mL / 1000 = 0.0995 L

0.068 m / 0.0995L = 0.683

<em>If we convert moles in mmoles, we can also get Molarity (M)</em>

<em>mmoles / mL = M</em>

<em>0.068 moles . 1000 = 68 mmoles</em>

<em>68 mmmoles / 99.5mL = 0.683</em>

8 0
3 years ago
Which organelle if empty would cause the plant to wilt
valentina_108 [34]
The vacuole because the less water it has the more it will wilt<span>. The reason of it </span>wilting<span> is because the cells shrink which is the </span>cause<span> of </span>wilting<span>.</span>
8 0
4 years ago
Use lewis theory to determine the formula for the compound that forms between sr and se
katen-ka-za [31]

\text{Sr}\text{Se}

<h3>Explanation</h3>

The Lewis Theory predicts the way atoms form bond based on their numbers of valence electrons. Atoms gain or lose electrons as they seek to achieve either a complete eight-electron valence shell or an empty shell, exposing the inner eight-electron shell. Both electron configurations are stable and are known as "octets". However, atoms tend to prefer the configuration with the minimum number of electron transfers.

Strontium (Sr) is found in group 2 (II A) of a modern periodic table. A neutral atom of strontium has two valence electrons in its valence shell.

Selenium (Se) is found in group 16 (VI A) of a modern periodic periodic table. A neutral atom of selenium contains six electrons in its valence shell.

Strontium needs to either lose two electrons or gain six electrons to achieve a configuration with eight electrons in its valence shell. Losing two electrons take less energy. Strontium is thus expected to lose two electrons.

Similarly, selenium would prefer gaining two electrons to losing six electrons. It is expected to gain two electrons.

As a result, a strontium atom would supply exactly two electrons. At the same time, a  As a result, a selenium atom would accept the two electrons, no more or no less. The two elements would combine at a one to one ratio. In other words:

n(\text{Sr, atoms}) : n(\text{Se, atoms}) \\= n(\text{Sr, electrons lost}) : n(\text{Se, electrons gained}) \\= 1:1

Each electron carries one negative charge. As a result, atoms that have gained electrons demonstrate a negative charge, whereas atoms that have lost electrons appear to be positive. By convention, atoms with a positive charge shall be written in front of those with a negative charge in a formula.

Sr atoms have lost electrons. Accordingly, they carry positive charges and shall be written at the beginning of the formula.

Se atoms have gained electrons. Accordingly, they carry negative charges and shall be placed to the end of the formula.

Thus the chemical formula: \text{Sr}\text{Se}

4 0
3 years ago
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