The reason why there is a difference between free-fall acceleration is a centrifugal force.
I attached a diagram that shows how this force aligns with the force of gravity.
From the diagram we can see that:

Where g' is the free-fall acceleration when there is no centrifugal force, r is the radius of the planet, and w is angular frequency of planet's rotation.

is the latitude.
We can calculate g' and wr^2 from the given conditions in the problem.

Our final equation is:

Colatitude is:

The answer is:
<span> Space satellites, laser beams, mirrors</span> are used to calculate the distance a continent has moved in a year.
Therefore, your correct answer would be "all of the above".
The answer would be tectonic. hope this helps (:
Answer:
Acceleration = 10.06 m/s²
Explanation:
1 mile = 1.6093km
1609.3m = 1 mile
1 m =
mile
50.0 miles/hour =
m/s
= 22.35m/s
from equation
S = Ut + 1/2 at²
v = U + at
22.35 = 0 + a * 2.22
a = 22.35 ÷ 2.22
= 10.06 m/s²