Answer:
The Troposphere is the lowermost portion of Earth’s atmosphere. It is the densest layer of the atmosphere and contains approximately 75 percent of the mass of the atmosphere and almost all the water vapor and aerosol. The troposphere extends from the Earth’s surface up to the tropopause where the stratosphere begins.
Explanation:
Answer:
The magnitude and direction of the acceleration of the particle is 
Explanation:
Given that,
Mass 
Velocity 
Charge 
Magnetic field 
We need to calculate the acceleration of the particle
Formula of the acceleration is defined as


We need to calculate the value of 


Now, put the all values into the acceleration 's formula


Negative sign shows the opposite direction.
Hence, The magnitude and direction of the acceleration of the particle is 
It is required an infinite work. The additional electron will never reach the origin.
In fact, assuming the additional electron is coming from the positive direction, as it approaches x=+1.00 m it will become closer and closer to the electron located at x=+1.00 m. However, the electrostatic force between the two electrons (which is repulsive) will become infinite when the second electron reaches x=+1.00 m, because the distance d between the two electrons is zero:

So, in order for the additional electron to cross this point, it is required an infinite amount of work, which is impossible.
An object need to move in a straight line in the same direction in equal intervals of time in order for total distance traveled and displacement to be equal.
This is true because they are the same type of pole.