<span>The answer is
0.124639157 pounds.
I converted it. </span><span />
<span>the max number of electrons that can occupy a box in an orbital filling diagram at any energy level is 2.
</span><span>A. 2</span><span>
</span>
0.139 moles of plutonium are present in a sample containing 8.4 x 10²² atoms of Pt.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated using the following expression:
no of moles = no of molecules ÷ 6.02 × 10²³
According to this question, 8.4 × 10²² atoms of plutonium are present in the molecule of plutonium.
no of moles = 8.4 × 10²² = 6.02 × 10²³
no of moles = 1.39 × 10-¹
no of moles = 0.139moles
Therefore, 0.139 moles of plutonium are present in a sample containing 8.4 x 10²² atoms of Pt.
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The new volume : V₂ = 2454.8 L
<h3>Further explanation</h3>
Given
V₁=2240 L
P₁=760 mmHg
T₁=320 K
P₂=700 mmHg
T₂=323 K
Required
Volume V₂
Solution
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
760 mmHg x 2240 L /320 K = 700 mmHg x V₂/323 K
V₂=(P₁V₁T₂)/P₂T₁
V₂=(760 x 2240 x 323)/(700 x 320)
V₂ = 2454.8 L