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Alex17521 [72]
3 years ago
8

Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m. Simu

ltaneously, each puck is given a quick push, and they begin to slide directly toward each other. Puck A moves with a speed of 1.30 m/s, and puck B moves with a speed of 1.70 m/s. What is the distance that puck A covers prior to the collision?

Physics
2 answers:
swat323 years ago
8 0

Answer:

7.8 m

Explanation:

See the attachement

salantis [7]3 years ago
6 0

Answer: pick A moves 10.2 metre

Explanation: since they were given a quick push simultaneously the product of their distance moved and velocity would be equal.

Let the distance moved by puck B x then that of puck A would be 18-x.

So therefore we have that,

1.3*(18-x) = 1.7*x

23.4 - 1.3x = 1.7x

23.4=3x

Making x subject of formula we have

x = 23.4/3 = 7.8m

But the distance moved by puck A is 18-x. So therefore,

18-7.8=10.2meter

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Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia
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Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

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to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

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time B = x / 7     ...................1

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