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In gamma-ray astronomy, gamma-ray bursts are immensely energetic explosions that have been observed in distant galaxies. They are the brightest and most energetic electromagnetic events known to occur in the universe. Bursts can last from ten milliseconds to several hours. b
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Answer:
thx for the points but I didn't understand
Answer is: <span> the equilibrium concentration of Br</span>₂ is 0,02 mol/L.<span>
</span>Chemical reaction: Br₂ + Cl₂ → 2BrCl.
Kc = 7,0.
c₀(Br₂) = 0,25 mol ÷ 3 L.
c₀(Br₂) = 0,083 mol/L.
c₀(Cl₂) = 0,55 mol ÷ 3 L.
c₀(Cl₂) = 0,183 mol/L.
Kc = c(BrCl)² ÷ c(Br₂) · c(Cl₂).
7 = (2x)² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
7 = 4x² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
Solve q<span>uadratic equation: x = 0,063 mol/L.
</span>c(Br₂) = 0,083 mol/L - 0,063 mol/L = 0,02 mol/L.
To balance a chemical reaction, we need to remember that the number of each atom in the reactant and the product side of the equation should be equal. So, from the reaction <span>P4(s) + Cl2(g) = PCl3(l), there are 4 P atoms in the reactant, the P atoms in the prodcut side should be 4 as well. We balance as follows:
</span> P4(s) + 6Cl2(g) = 4PCl3(l)
<span>
Therefore, the coefficient of the PCl3 should be 4.
</span>
Answer:
<em>The energy of atomic orbitals increases as the principal quantum number, n, increases. In any atom with two or more electrons, the repulsion between the electrons makes energies of subshells with different values of I differ so that the energy of the orbitals increases within a shell in the order s< p <d<f. Figure 1 depicts how these two trends in increasing energy relate. The 1s orbital at the bottom of the diagram is the orbital with electrons of lowest energy. The energy increases as we move up to the 2s and then 2p, 3s, and 3p orbitals, showing that the increasing n value has more influence on energy than the increasing I value for small atoms. However, this pattern does not hold for larger atoms. The 3d orbital is higher in energy than the 4s orbital. Such overlaps continue to occur frequently as we move up the chart.</em>
