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Dmitrij [34]
3 years ago
11

6Atoms of which of the following elements will

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
3 0

Answer:i think it's b

Explanation:

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What other elements does iron commonly bonds with.
Neko [114]

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

it can bond with oxygen to form rust or iron oxide. and it can bond with carbon to form steel.

Here's another one: Iron bonds with lots of things: Oxygen (Ferric Oxide = rust),Chlorine (Ferric Chloride]), Fluorine, ... , even other Iron (in aMetallic Bond or crystal).

Hope it helps.

Have a nice day hyung/noona!~  ̄▽ ̄❤️

5 0
2 years ago
Why do we experience the changing of the seasons on earth
iren2701 [21]

<u>Answer:</u>

Earth's axis and position around the sun.

<u>Explanation:</u>

Earth's tilted axis causes the seasons to change. Throughout the year, different parts of Earth acquire the Sun's most direct rays(Or heat) because of the orbital rotation of Earth. So, when the North Pole tilts toward the Sun, it's summer inside the Northern Hemisphere. And whilst the South Pole tilts towards the Sun, it is winter within the Northern Hemisphere and vise versa.

4 0
2 years ago
An unbalanced equation is shown. In this reaction, 200.0 g of FeS2 is burned in 100.0 g of oxygen, and 55.00 g of Fe2O3 is produ
Crazy boy [7]
<span>4FeS2 + 11O2 = 2Fe2O3 + 8SO2</span>

Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.

Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3

To find for the theoretical yield, we first determine the limiting reactant.

100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2

Therefore, the limiting reactant is O2.

Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3

Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%
3 0
2 years ago
1. What type of battery was made by alternating layers of silver, zinc and blotting paper soaked in salt?
Sunny_sXe [5.5K]

Answer:

voltaic piles

Explanation:

:3

4 0
3 years ago
Read 2 more answers
glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

6 0
3 years ago
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