N=1 shell contains 2 electrons.
n=2 shell contains 5 electrons.
n=2 is the outermost shell. Therefore there were 5 electrons before sharing.
6 electrons are being shared between 2 nitrogen atoms.
Pair of electrons form a covalent bond. Therefore 3 pair of electrons will form 3 bonds.
B is true since evaporation changes a liquid into a gas and dondensation turns a gas into a liquid
<u>Given:</u>
Volume of air inhaled V = 0.56 L
Temperature T = 37 C = 37 +273 = 310 K
Pressure P = 744 mmHg = 744/760 = 0.979 atm
% N2 in air = 78%
<u>To determine:</u>
The moles of N2 inhaled in one breath
<u>Explanation:</u>
Step 1: Calculate the moles of air inhales
Based on the ideal gas law:
PV = nRT
where P = pressure, T = temperature, V = volume, n = # moles
R = gas constant = 0.0821 L atm/mol-K
n = PV/RT = 0.979 * 0.56/0.0821*310 = 0.0215 moles of air
Step 2: Calculate the moles of N2
It is given that air contains 78% N2
Therefore:
moles of N2 = 0.0215 * 78/100 = 0.0168 moles
Ans: moles of N2 = 0.0168
The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
<h3>
What is the amount of Amoxicillin dose given to the child?</h3>
The amount of Amoxicillin dose given to the child is calculated as follows;
amount of Amoxicillin dose = weight of the child x dosage prescribed
<h3>What is the weight of the child in pounds (lb) </h3>
The weight of the child in pounds (lb) is calculated as follows;
1 lb = 0.453592 kg
85.4 lb = ?
= 85.4 x 0.453592 kg
= 38.74 kg
amount of Amoxicillin dose = 38.74 kg x 45 mg/kg
amount of Amoxicillin dose = 1,743.3 mg
Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
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The complete question is below:
A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.
