Given :
Mass of water, m = 2 grams.
The temperature of water drops from 31 °C to 29 °C .
The specific heat of water is 4.184 J/(g • °C).
To Find :
Amount of heat lost in this process.
Solution :
We know, heat lost is given by :
Therefore, amount of heat lost in this process is 16.736 J.
Answer:
The answer is below
Explanation:
a) The change in energy is the difference between the final energy and the initial energy.
ΔE (energy change) = Ef (final energy) - Ei (initial energy)
The negative sign shows that energy is lost to the environment. Hence 0.334 J is lost to the environment.
b) According to the law of conservation of energy, energy cannot be created or destroyed but transformed from one form to another.
The oscillating object loses energy due to wind resistance, friction between the spring and the object. Given that the air is frictionless, hence the energy loss is due to friction which is converted to heat.