Question

Calculate the percent yield when 500 grams of carbon dioxide react with an excess of water to produce 640 grams of carbonic acid. CO2 + H2O ---> H2CO3

Answer 1

Answer:

The answer to your question is 90.8%

Explanation:

Balanced Reaction

                         CO₂  +   H₂O   ⇒    H₂CO₃

Process

1.- Calculate the theoretical production of H₂CO₃

Molecular mass of CO₂ = 12 + 32 = 44 g

Molecular mass of H₂CO₃ = 2 + 12 + 48 = 62 g                          

                          44 g of CO₂  ----------------  62 g of H₂CO₃

                        500 g of CO₂ ---------------    x

                           x = (500 x 62) / 44

                           x = 704.54 moles of H₂CO₃

2.- Calculate the percent yield

Formula

$Percent yield = \frac{experimental amount}{theoretical amount} x 100$

Substitution

$Percent yield = \frac{640}{704.54} x 100$

Result = 90.8 %