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sergey [27]
3 years ago
7

Two firefighters are fighting a fire with identical water hoses and nozzles, except that one is holding the hose straight so tha

t the water leaves the nozzle in the same direction it comes, while the other holds it backward so that the water makes a U-turn before being discharged. Which firefighter will experience a greater reaction force?
Physics
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

The one that holds it backward will experience a greater reaction force.

Explanation:

Newtons third law of motion states that in every action there is equal and opposite reaction. The action force of making the water  leave the nozzle for the firefighter who holds the hose backwards is greater than that for the fire fighter holding it straight. The water requires a a greater momentum and force to make a u-turn before leaving the nozzle. Hence the reaction force for the hose held backwards is greater

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Answer:

The value of work input to the compressor W_{in} = 1505.7 \frac{KJ}{kg}

The value of entropy generation inside the compressor

S_{gen} = - 1.064 \frac{KJ}{kg K}

Explanation:

Initial pressure P_{1} = 100 k pa

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At initial pressure P_{1} = 100 k pa the steam is saturated vapour. From the steam tables the value of volume at this state is v = 1.673 \frac{m^{3} }{kg}

Thus the work input to the compressor W_{in} = v dP

⇒ W_{in} = v  ( P_{2} - P_{1} )

⇒ W_{in} = 1.673 ( 1000 - 100 )

⇒ W_{in} = 1505.7 \frac{KJ}{kg}

The isentropic efficiency is  = 85 %

So the work input to the compressor W_{in} = \frac{1505.7}{0.85}

⇒ W_{in} =  1771.42 \frac{KJ}{kg}

This is the value of work input to the compressor.

S_{gen} = - R \ln \frac{P_{2} }{P_{1} }

S_{gen} =  - 0.462 \ln \frac{1000}{100}

S_{gen} = - 1.064 \frac{KJ}{kg K}

This is the value of entropy generation inside the compressor.

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