Mary used one big bag of flour. She baked four loaves of bread. Then, she used the remaining flour to make 48 muffins. How much
1 answer:
Answer:
Amount of flour in the bag when Mary began =
Step-by-step explanation:
Given:
Number of baked loaves of bread made from flour = 4
Number of muffins made from flour = 48
To find: Amount of flour in the bag when Mary began
Solution:
Let x denotes amount of flour used to make one baked loave of bread and y denotes amount of flour used to make one muffin.
So,
Amount of flour used to make 4 baked loaves of bread = 4 x
Amount of flour used to make 48 muffins = 48 y
Amount of flour in the bag when Mary began =
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Answer:
p ∈ IR - {6}
Step-by-step explanation:
The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2
is all R2 ⇔
And also u and v must be linearly independent.
In order to achieve the final condition, we can make a matrix that belongs to using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.
Let's make the matrix :
We used the first vector ''u'' as the first column of the matrix A
We used the second vector ''v'' as the second column of the matrix A
The determinant of the matrix ''A'' is
We need this determinant to be different to zero
The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that
We can write : p ∈ IR - {6}
Notice that is ⇒
If we write , the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.
For more context let's look at the first equation in the problem that we can apply this to:
Through zero property we know that the factor
can be equal to zero as well as 
. This is because, even if only one of them is zero, the product will immediately be zero.
The zero product property is best applied to factorable quadratic equations in this case.
Another factorable equation would be
since we can factor out 
and end up with 
. Now we'll end up with two factors, and 
, which we can apply the zero product property to.
The rest of the options are not factorable thus the zero product property won't apply to them.
For more context let's look at the first equation in the problem that we can apply this to:
Through zero property we know that the factor
The zero product property is best applied to factorable quadratic equations in this case.
Another factorable equation would be
The rest of the options are not factorable thus the zero product property won't apply to them.