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strojnjashka [21]
4 years ago
6

A 0.140 m high cylinder

Physics
1 answer:
solmaris [256]4 years ago
5 0

Answer:

The value of pressure inside the cylinder is 18.68 K Pa.

Explanation:

Given data

Height h = 0.14 m

Density \rho = 13600 \frac{kg}{m^{3} }

We know that

Pressure inside the cylinder is given by the formula

P = \rho g h ------- (1)

here

\rho = density of fluid = 13600 \frac{kg}{m^{3} }

g = acceleration due to gravity = 9.81 \frac{m}{s^{2} }

h = height of the cylinder = 0.14 m

Put all the values in above equation

P = 13600 × 9.81 × 0.14

P = 18678.24 Pa

P = 18.68 K Pa

Therefore the value of pressure inside the cylinder is 18.68 K Pa

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Answer:

Option D

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Explanation:

Power, P is also given as the product of voltage and current, expressed as P=VI

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Taking 12 V for voltage across and 350A for current across circuit then power will be

P=350*12=4200 W

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Wolfgang pauli hypothesized an exclusion principle. This principle says two electrons in an atom cannot have the same what?.
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<h3>What is Pauli's exclusion principle ?</h3>

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In lab, your instructor generates a standing wave using a thin string of length L = 1.65 m fixed at both ends. You are told that
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Answer:

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This means that the relation between the wavelength and the length of the string is

3\lambda/2 = L

By definition, this standing wave is at the third harmonic, n = 3.

Furthermore, the standing wave equation is as follows:

y(x,t) = (A\sin(kx))\sin(\omega t) = A\sin(\frac{\omega}{v}x)\sin(\omega t) = A\sin(\frac{2\pi f}{v}x)\sin(2\pi ft) = A\sin(\frac{2\pi}{\lambda}x)\sin(\frac{2\pi v}{\lambda}t) = (2.45\times 10^{-3})\sin(5.7x)\sin(59.94t)

The bead is placed on x = 0.138 m. The maximum velocity is where the derivative of the velocity function equals to zero.

v_y(x,t) = \frac{dy(x,t)}{dt} = \omega A\sin(kx)\cos(\omega t)\\a_y(x,t) = \frac{dv(x,t)}{dt} = -\omega^2A\sin(kx)\sin(\omega t)

a_y(x,t) = -(59.94)^2(2.45\times 10^{-3})\sin((5.7)(0.138))\sin(59.94t) = 0

For this equation to be equal to zero, sin(59.94t) = 0. So,

59.94t = \pi\\t = \pi/59.94 = 0.0524~s

This is the time when the velocity is maximum. So, the maximum velocity can be found by plugging this time into the velocity function:

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