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3 years ago

A 0.140 m high cylinder

Physics

1 answer:

solmaris [256]3 years ago

5 0

Answer:

The value of pressure inside the cylinder is 18.68 K Pa.

Explanation:

Given data

Height h = 0.14 m

Density $\rho$ = 13600 $\frac{kg}{m^{3} }$

We know that

Pressure inside the cylinder is given by the formula

P = $\rho$ g h ------- (1)

here

$\rho$ = density of fluid = 13600 $\frac{kg}{m^{3} }$

g = acceleration due to gravity = 9.81 $\frac{m}{s^{2} }$

h = height of the cylinder = 0.14 m

Put all the values in above equation

P = 13600 × 9.81 × 0.14

P = 18678.24 Pa

P = 18.68 K Pa

Therefore the value of pressure inside the cylinder is 18.68 K Pa

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3 years ago

Water ice has a density of 0.91 g/cm2, so it will float in liquid water. Imagine you have a cube of ice, 10 cm on a side. a. Wha

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Answer:

(i) W = 8.918 N

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Explanation:

Part a)

As we know that weight of cube is given as

$W = mg$

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here we know that

$\rho = 0.91 g/cm^3$

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now the mass of the ice cube is given as

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now weight is given as

$W = 0.910 \times 9.8 = 8.918 N$

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

$W_{displaced} = 8.918 N$

So here volume displaced is given as

$\rho_{water}Vg = 8.918$

$1000(V)9.8 = 8.918$

$V = 9.1 \times 10^{-4} m^3$

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

$W = \rho_{water} (L^2 d) g$

$8.918 = 1000(0.10^2 \times d) 9.8$

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Answer:

Explanation:

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for proton

q = e , v = vi , B = Bk

F = e ( vi x Bk )

= Bev - j

= - Bevj

The direction of force is along negative of y axis or -y - axis.

for electron

q = - e , v = vi , B = Bk

F = - e ( vi x Bk )

= - Bev - j

= Bevj

The direction of force is along positive of y axis or + y - axis.

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2 years ago

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