Answer:
The acceleration of the wallet is 
Explanation:
Given that,
Radius of purse r= 2.30 m
Radius of wallet r'= 3.45 m
Acceleration of the purse 
We need to calculate the acceleration of the wallet
Using formula of acceleration

Both the purse and wallet have same angular velocity








Hence, The acceleration of the wallet is 
The appropriate response is the third one. A generator is utilized to enact the control poles which contain radioactive isotopes. Once initiated, these isotopes start an atomic splitting chain response. Water in a cooling tank monitors the rate of response as electrons radiated from the response are encouraged through wires to homes and organizations.
Recall that mass is the amount of matter present in a body. That means it's a property that is consistent regardless of the body's current location, gravity's pull on the body, etc.
Let's not confuse mass with weight (which is a force computed as Weight = mass x acceleration). Mass will remain constant and that means that whether the object is on Earth or on Mars, its mass remains the same. Thus, the object will still have 2.00 kg as mass on Mars.
Answers: 2.00 kilograms
Answer:
lower
Explanation:
The lower the value of the coefficient of friction, the lower the resistance to sliding.
The coefficient of friction is the ratio of the frictional force and the normal force pressing two surfaces in contact together.
U =
U is the coefficient of friction
F is the frictional force
N is the normal force
We see that coefficient of friction is directly proportional to frictional force.