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strojnjashka [21]
4 years ago
6

A 0.140 m high cylinder

Physics
1 answer:
solmaris [256]4 years ago
5 0

Answer:

The value of pressure inside the cylinder is 18.68 K Pa.

Explanation:

Given data

Height h = 0.14 m

Density \rho = 13600 \frac{kg}{m^{3} }

We know that

Pressure inside the cylinder is given by the formula

P = \rho g h ------- (1)

here

\rho = density of fluid = 13600 \frac{kg}{m^{3} }

g = acceleration due to gravity = 9.81 \frac{m}{s^{2} }

h = height of the cylinder = 0.14 m

Put all the values in above equation

P = 13600 × 9.81 × 0.14

P = 18678.24 Pa

P = 18.68 K Pa

Therefore the value of pressure inside the cylinder is 18.68 K Pa

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Explanation:

The traveler observed that the temperature in Fahrenheit is five times the value of the temperature in Celsius, therefore:

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Using the second expression on the first, we can solve for the temperature in Celsius, this is done below:

\frac{9}{5}*C + 32 = 5*C\\\frac{9}{5}*C - 5*C = -32\\\frac{9*C - 25*C}{5} = -32\\\frac{-16*C}{5} = -32\\-16*C = -32*5\\-16*C = -160\\C = \frac{-160}{-16} = 10\º\text{C}\\F = 5*C = 5*10 = 50\º\text{F}

The observed temperature was 10º Celsius or 50º Fahrenheit.

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(c) 16 m/s²

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The acceleration is the first time-derivative of the velocity.

a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}

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