RAKE A BREAK AND GO BACK TO IT QUEEN YOULL GET YA ANSWER
I do not know of the following in your class, but the wall is still and non-moving, while the hockey player is pushing off of it, as stated. So, this is not inertia, for a fact, because the wall is not moving towards the hockey player.
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> = initial velocity, <em>v</em> = final velocity, <em>a</em> = acceleration, and ∆<em>x</em> = distance traveled.
So
<em>v</em>² - (15 m/s)² = 2 (6.5 m/s²) (340 m)
<em>v</em>² = 4645 m²/s²
<em>v</em> ≈ 68.15 m/s
Answer:
the area of the rectangular field is 10.5 m²
Explanation:
Given;
length of the rectangular field, L = 42 cm = 0.42 m
breadth of the rectangular field, b = 25 m
The area of the rectangular field is calculated as follows;
Area = Length x breadth
Area = 0.42 m x 25 m
Area = 10.5 m²
Therefore, the area of the rectangular field is 10.5 m²
